Answer:
All real numbers less than or equal to 18
Step-by-step explanation:
Let
x -----> the number
we know that
The algebraic expression that represent this situation is
Solve for x
Multiply by 6 both sides to remove the fractions
Combine like terms left side
Adds 18 both sides
Subtract 5x both sides
Rewrite
All real numbers less than or equal to 18
Answer:
x = -8
x = 8
Step-by-step explanation:
x(18 – x) = 2(9x – 32)
distribute
18x - x² = 18x - 64
Subtract 18x from both sides
-x² = -64
multiply both sides by -1
x² = 64
Take the square root of both sides
x = ± 8
x = -8
x = 8
The answer to this question is b
Answer:
(0,3) and (1,4) are solution sets of given system
Step-by-step explanation:
Given that:
y= 3x^2−2x+3 ------------- eqA
y = x + 3 ------------------ eqB
Putting value of y from eqB to eqA
x + 3 = 3x^2−2x+3
Taking all variables to left side:
Signs pf transferred terms will be changed
3x^2−2x+3 - x - 3 = 0
Adding like terms we get:
3x^2−3x = 0
Dividing both sides by 3 we get:
x^2 - x = 0
Now take x common:
x(x-1)= 0
So
x = 0 and x = 1
Now put value in eqB
y = 0 + 3 and y= 1 + 3
we get:
y = 3 and y = 4
So solution sets are:
(0,3) and (1,4)
i hope it will help you!
