Answer:
![\sqrt[12]{55296}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B55296%7D)
/2
Step-by-step explanation:
![\sqrt[4]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B6%7D)
/![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
=1.2422
![\sqrt[12]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B27%7D)
/2=0.66 <-- not matching with the top expression.
![\sqrt[4]{24}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B24%7D)
/2=1.11<--not matching with the top expression.
/2=1.2422<-- matches!!
![\sqrt[12]{177147}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B177147%7D)
/3=0.91<-- not matching with the top expression.
Answer:
Step-by-step explanation:
To isolate r, we're going to need to do some algebraic manipulation.
Multiply both sides by r:
Divide both sides by a:
Hope this helps!
The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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Answer:
Just hit continue.
Step-by-step explanation:
The predicted amount is for the second button only.
