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2 years ago

The distance from Earth to the Moon is about 384,400 km. How many light-years is this?

Advanced Placement (AP)

2 answers:

storchak [24]2 years ago

8 0

Answer:

1/2 light years Hope it helps

Explanation:

vagabundo [1.1K]2 years ago

3 0

Explanation:

1/2 light years. because light travels at 386, 000 ,000 so, half of it will be the distance

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Question: Given P(X) = 0.5, P(Y) = 0.4, and P(Y|X) = 0.3, what are P(X and Y) and P(X or Y)? (3 points)

Rufina [12.5K]

Answer:

$P(x\ and\ y) = 0.15$

$P(x\ or\ y) = 0.75$

Explanation:

Given

$P(x) = 0.5$

$P(y) = 0.4$

$P(y|x) = 0.3$

Solving (a): $P(x\ and\ y)$

In probability, this is calculated as:

$P(x\ and\ y) = P(x) * P(y|x)$

This gives:

$P(x\ and\ y) = 0.5 * 0.3$

$P(x\ and\ y) = 0.15$

Solving (b): $P(x\ or\ y)$

In probability, this is calculated as:

$P(x\ or\ y) = P(x) + P(y) - P(x\ and\ y)$

This gives:

$P(x\ or\ y) = 0.5 + 0.4 - 0.15$

$P(x\ or\ y) = 0.75$

5 0

2 years ago

Conflicts are rare and are likely only when two different personalities work closely together on a project.

Katyanochek1 [597]

This is false. If two given people of similar or different personalities work together conflicts are always likely and are not rare.

3 0

2 years ago

Read 2 more answers

The total estimated cost of attending a public two-year college in Hasani’s home town last year was $2,265. The cost of attendin

kicyunya [14]

The future worth of a current amount that has a compound interest can be calculated through the equation,

F = P x (1 + r)^n

Where P is the present worth, F is the future worth, r is the rate and n is the number of years. Substituting the known values to the equation,

F = ($2,265)(1 + 0.05)^2 = $2,497.163

Thus, the amount that Hasani will pay for his second year is approximately $2,497.163.

8 0

3 years ago

Read 2 more answers

Find the solution to the differential equation dy/dx = cos(x) / y2 , where y(π/2) = 0.

AysviL [449]

Answer:

$y=2\sqrt{\sin \left(x\right)-1},\:y=-2\sqrt{\sin \left(x\right)-1}$

Explanation:

$\frac{dy}{dx}=\frac{\cos \left(x\right)}{y}2$

$y'\:=\frac{\cos \left(x\right)}{y}\cdot \:2$

$yy'\:=2\cos \left(x\right)$

$yy'\:=2\cos \left(x\right):\quad \frac{y^2}{2}=2\sin \left(x\right)+c_1$

$\frac{y^2}{2}=2\sin \left(x\right)-2$

$y=2\sqrt{\sin \left(x\right)-1},\:y=-2\sqrt{\sin \left(x\right)-1}$

3 0

2 years ago

The specific heat of water is 4.186 J g-1 °C-1. What is the amount of energy, in J, required to heat 10.00 g of water 20.00 °C?

sineoko [7]

Answer:

Required heat q = 0.8372 j

Explanation:

Given:

Specific heat of water = 4.186 J g-1 °C-1

Mass m = 10 g = 0.01 kg

Temperature t = 20.00 °C

Find:

Required heat q

Computation:

q = cmΔT

Required heat q = [4.186][0.01][20]

Required heat q = 0.8372 j

7 0

2 years ago