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meriva
3 years ago
13

If r = 8 units and x = 5 units, then what is the volume of the cylinder shown above?

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
I hope this helps you

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Solve −6x+6−7=2x+8 for x. How would I solve this?
MakcuM [25]

Answer:

Step-by-step explanation:

−6x+6−7=2x+8

-1-8=2x+6x

8x=-9

x= -\frac{9}{8}

7 0
3 years ago
Rosa makes a small flower garden outside the clubhouse the area of the garden is 851 m² if the length of the garden is 23 m what
attashe74 [19]
So the garden has a rectangular shape, of 23 m of length, x meters of width and 851 m^2 area, the area is calculated with this formula:
area = length*width
lets solve for width:
width = area/length
if we substitute our data we have:
width = 851/23
width = 37
therefore the width of the garden is 37 m
4 0
3 years ago
The top surface of a desk has a length of 5.6 feet. The length is 4 times its width. What is the width of the desk.
lys-0071 [83]
22.4ft.

5.6 * 4 = 22.4
area
4 0
3 years ago
Read 2 more answers
A pharmacist receives a special request from an ophthalmologist to prepare a fortified tobramycin ophthalmic solution.
Harrizon [31]

Answer:

2/7 ml

Step-by-step explanation:

When we have a solution expressed in Q mg/ml, the concentration is (Q/10)%.

For example, a solution of 3 mg/ml is a 3/10=0.3% concentration solution, a solution of 40 mg/ml is a 40/10=4% concentration solution.

<em>Why? </em>

Q mg/ml means that 1 ml of solution has Q mg of the drug or active component. So, 100 ml have 100*Q mg.

But 100*Q mg = Q/10 grams.

If a solution has Q/10 grams in 100 ml, then it is a (Q/10)% concentration.

Now, we have 5 ml of a solution that contains tobramycin, 3 mg/ml (each ml has 3 mg of tobramycin).

This means that the 5 ml contain 15 mg of  tobramycin.

On the other hand, we have another solution S containing 40 mg/ml of tobramycin. This means that each ml of S contains 40 mg of tobramycin.

Let x be the amount of ml of S we have to add to our first 5 ml.

If 1 ml of S contains 40 mg of  tobramycin, x ml contain 40*x mg.

If we add this x ml to our first 5 ml, we have 5+x ml containing 15+40*x mg of  tobramycin.  

Now, cross-multiply to get how much tobramycin contains 1 ml of this new solution.

5+x ml ____contain____15+40*x mg of  tobramycin

   1 ml ____contains____? mg

And we have

\large \frac{5+x}{1}=\frac{15+40x}{?}\Rightarrow ?=\frac{15+40x}{5+x}

as a result, we have a solution of  

\large \frac{15+40x}{5+x}\;mg/ml

We want to prepare a solution 0.5% in concentration.

Using what we state at the beginning, we need to find a value x such that

\large \frac{(15+40x)/(5+x)}{10}=0.5

solving for x

\large \frac{(15+40x)/(5+x)}{10}=0.5\Rightarrow \frac{15+40x}{5+x}=5\Rightarrow 15+40x=25+5x\Rightarrow\\\\\Rightarrow 40x-5x=25-15\Rightarrow 35x=10\Rightarrow x=10/35=2/7 \;ml

So, we have to add just 2/7 ml of the stronger solution.

6 0
4 years ago
Complete the steps to solve this linear equation: 2x + 9(x – 1) = 8(2x + 2) – 5
alexdok [17]
I think it’s 3. Sorry if I’m wrong tho
4 0
3 years ago
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