Answer:
y=1/2x+5
Step-by-step explanation:
Plug it into the formula for a point and a slope.
(y-(y(subscript 1)))=(m)(x-(x(subscript 1)))
Y-8=1/2(x-6)
Then multiply the 1/2 to the x and -6. After you do that, move everything so that it has y by itself on the left. Your ending should be y=1/2x+5.
I ain't Joseph but what's wrong?
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
Answer:
X is just the variable or missing edge, side, angle .etc that you are looking for
Step-by-step explanation:
A quadrilateral always has interior angles that add up to 360 degrees.
