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Helga [31]
3 years ago
7

Solve −6x+6−7=2x+8 for x. How would I solve this?

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

Step-by-step explanation:

−6x+6−7=2x+8

-1-8=2x+6x

8x=-9

x= -\frac{9}{8}

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What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
3 years ago
The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
What is the area of the shaded region? (Use 3.14 for Pi) *
love history [14]

Answer:

The area of the shaded region is the difference between the areas of the rectangle and the square.

Step-by-step explanation:

8 0
3 years ago
Write the expression in expanded form that is equivalent to 3(7d +4e)
pickupchik [31]

Answer:

21+4

Step-by-step explanation:

3 times 7=21

3 times4=12

21d+4e

4 0
2 years ago
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Which shows the image of ΔRST after the rotation (x, y) → (y, –x)?
Leona [35]
Did you mean to include an image?
5 0
3 years ago
Read 2 more answers
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