Answer:
d) one solution; (4, 1)
Step-by-step explanation:
It often works well to follow problem directions. A graph is attached, showing the one solution to be (4, 1).
_____
You know there will be one solution because the lines have different slopes. Each is in the form ...
y = mx + b
where m is the slope and b is the y-intercept.
The first line has slope -1 and y-intercept +5; the second line has slope 1 and y-intercept -3. The slope is the number of units of "rise" for each unit of "run", so it can be convenient to graph these by starting at the y-intercept and plotting points with those rise and run from the point you know.
To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
2/8+6/8 = 1
1 + 1 + 1 =3
now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
therefore, we get 3/10. because this can't be simplified, this will be your final answer.
Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:



±

where the value
will be taken from the z-table for 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table the value of
corresponding to 0.0975 is 1.96
±

±

± 
% ±
%
so the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
The area would be 30. it would be 6x5