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Fed [463]
3 years ago
13

Find the simple interest and amount when principal = Rs. 6000, rate = 6% per annum and time = 4 years

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Given:

Principal = Rs. 6000

Rate of simple interest = 6% per annum.

Time = 4 years

To find:

The simple interest and amount.

Solution:

Formula for simple interest:

I=\dfrac{P\times r\times t}{100}

Where, P is principal, r is the rate of interest and t is the number of years.

Putting P=6000, r=6 and t=4, we get

I=\dfrac{6000\times 6\times 4}{100}

I=60\times 6\times 4

I=1440

Now,

Amount=Principal+Interest

Amount=6000+1440

Amount=7440

Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.

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If m<mkl=83. m<jkl=127. and m<jkm=(9x-10). find the value of x
kirza4 [7]

MKL = 83, JKL = 127, JKM = 9x - 10        <em>given</em>

JKL + MKL = JKM                                    <em>angle addition postulate</em>

127 +  83  = 9x - 10                                 <em>substitution</em>

       210   = 9x - 10                                  <em>simplify (add like terms)</em>

       220  = 9x                                          <em>addition property of equality</em>

        \frac{220}{9} = x

3 0
3 years ago
Please help explanation if possible
Nookie1986 [14]

Answer:

y=-3x+5

Step-by-step explanation:

concepts: y=mx+b is slope intercept equation formula

m=slope

b= y intercept

Therefore we need to find the slope and y intercept

first find slope

m=\frac{y2-y1}{x2-x1}

let y2 be 2

let y1 be -4

let x2 be 1

let x1 be 3

\frac{2-(--4)}{1-3}

6/-2 = -3

m=-3

slope is -3

y= -3x+ b

we need find y intercept now

just plug in (1,2) into that equation

2=-3(1)+b

b=5

y=-3x+5

5 0
3 years ago
Brenda has money invested in Esti Transport. She owns two par value $1,000 bonds issued by Esti Transport, which currently sells
Debora [2.8K]

Answer:

B is the the answer but I'm not sure

7 0
3 years ago
What is the remainder of 10^2017 divided by 1001?
pashok25 [27]
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10


5 0
3 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
4 years ago
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