MKL = 83, JKL = 127, JKM = 9x - 10 <em>given</em>
JKL + MKL = JKM <em>angle addition postulate</em>
127 + 83 = 9x - 10 <em>substitution</em>
210 = 9x - 10 <em>simplify (add like terms)</em>
220 = 9x <em>addition property of equality</em>
= x
Answer:
y=-3x+5
Step-by-step explanation:
concepts: y=mx+b is slope intercept equation formula
m=slope
b= y intercept
Therefore we need to find the slope and y intercept
first find slope
m=
let y2 be 2
let y1 be -4
let x2 be 1
let x1 be 3

6/-2 = -3
m=-3
slope is -3
y= -3x+ b
we need find y intercept now
just plug in (1,2) into that equation
2=-3(1)+b
b=5
y=-3x+5
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic
10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)
Final Answer: 10
First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2