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BARSIC [14]
3 years ago
11

How would I solve this problem? We have to classify the angle pair and find the value of x.

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
Well the 2 angles are supplementary.
You would set up the equation like this:
(9x-7)+(7x-5)= 180
16x-12=180
+12
16x= 192
Divide both sides by 16
X= 12
Hope this helps
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I am thinking of a number.if you multiply my number by 4,add 4 to the product ,and then take 1/3 of the sum, the result is 6. fi
NeTakaya

6=((X*4)+4)/3

18=(X*4)+4

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7/2=X <— Answer

4 0
4 years ago
PLS HELP ME ILL MARK BRAINIEST
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Answer:

Question 1- 288.48

Step-by-step explanation:

depending on how they round your answer the number might look different.

V= Bh which means (pi)r^2(h)

3.14 x 1.25^2 x 4.9

V=24.040625 ~ 24.04

12 x 24.04

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3 years ago
Mia had $22. Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a
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8 0
3 years ago
The angle of elevation to the top of a skyscraper is measured to be 2 degrees from a point on the ground 1 mile from the buildin
Alex

Answer:

0.034921 miles or 1843774 feet tall

Step-by-step explanation:

Using trigonometric functions we know that x=rcos(\theta) and y=rsin(\theta) where \theta=angle and r is the hypotenuse of the triangle.

First we will calculate the hypotenuse using the x equation, since we know x = 1 mile (distance from the building on the ground) we have:

x=rcos(\theta)\\\\1=rcos(2)\\\\r=\frac{1}{cos(2)} \approx. 1.0061mi

Now we will calculate the height of the building using the y equation and so:

y=rsin(\theta)\\\\y=\frac{1}{cos(2)} \times sin(2) = \frac{sin(2)}{cos(2)}=tan(2)=0.034921mi

The building is 0.034921 miles or approximately 184.3774 feet tall.

4 0
3 years ago
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Dennis_Churaev [7]

Answer:

f(2) = -2

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f(2) = 2x - 6

f(2) = 2(2) - 6

f(2) = 4 - 6

f(2) = -2

4 0
3 years ago
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