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Alexeev081 [22]
3 years ago
6

Sorry for the crumbled paper someone pls help

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Answer:

Nasan po ba

Step-by-step explanation:

Paki sabi naman po sa comments

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Jack is a college athlete who has been weighing himself weekly on the same scale in the athletic center for the past few years.
Radda [10]

Answer:

a) Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=\pm 1.64

b) \bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error is given by:

SE = \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{9}}=1

c) \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And the margin of error is:

ME= z_{\alpha/2} \frac{\sigma}{\sqrt{n}} = 1.64

And then the confidence interval is be given by:

200-1.64 = 198.36

200+1.64 = 201.64

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 200 represent the sample mean

\mu population mean (variable of interest)

\sigma=3 represent the population standard deviation

n=9 represent the sample size  

Part a

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=\pm 1.64

Part b

The distribution for the sample mean is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error is given by:

SE = \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{9}}=1

Part c

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And the margin of error is:

ME= z_{\alpha/2} \frac{\sigma}{\sqrt{n}} = 1.64

And then the confidence interval is be given by:

200-1.64 = 198.36

200+1.64 = 201.64

8 0
3 years ago
PLS HELP WITH MATH HURRY
AlekseyPX

Answer:

x+3=9

Step-by-step explanation:

I hope this helped!

4 0
3 years ago
Read 2 more answers
Colton and Jonathan are employees for a company. Colton is making a salary of $103,092. Colton is earning a salary that is 42% h
Vinil7 [7]

Answer:

59,793.36

Step-by-step explanation:

you can multiply 103,092$ by (100%-42%=58%)

the result will be 59,793.36$

4 0
4 years ago
Read 2 more answers
James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described? A.10 B.32 C.42 D.3
vova2212 [387]
I think it'll be 32$ cuz thats what he started with.
4 0
3 years ago
Read 2 more answers
can someone please do 2 ixls for me please just tell me if u can and i will give u the login info please please PLEASE im at 60
iris [78.8K]
I will for you, sure
6 0
4 years ago
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