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beks73 [17]
3 years ago
8

HELP....................

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

-16

Step-by-step explanation:

5*-3.2= -16

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In what ways does algebra act as a tol to improve communication? How does algebra affect how people can learn from each other​
Serjik [45]

Answer:

it helps you in everyday life

Step-by-step explanation:

you can speak better

4 0
3 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
Amelia randomly selects two cards, with replacement, from a normal deck of cards. Calculate the probability that: the first card
Lena [83]

Answer:

1 / 2704

Step-by-step explanation:

Number of cards in a deck = 52

9 of clubs in a deck = 1

10 of clubs in a deck = 1

Probability = required outcome / Total possible outcomes

P(9 of club) = 1 / 52

With replacement ;

Then ;

P(10 of club) = 1 / 52

Hence,

P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704

3 0
3 years ago
ASAP HURRY.
saw5 [17]

won't it be 3.2 because A square has four sides so you multiply 0.8 by 4

6 0
3 years ago
Due to yet another road construction project in her city, Sarah must take a detour to get from work to her house. Not convinced
stiv31 [10]

Answer:

b). There is little to no evidence to conclude the mean driving time for the alternative route is different from the mean driving time of the detour.

Step-by-step explanation:

The most adequate statement to examine the proposition is that 'there is lack of adequate evidence to substantiate the claim that the mean time taken for driving through the detour and the alternative route is distinct.' This will help in testing that <u>there is a lack of evidence to establish the validity or truth of the proposition that if the detour is actually shorter than the alternative route or not</u>. No data has been provided to clarify that the mean driving time in both routes traveled by Sarah was varied. Hence, <u>option b</u> is the correct answer.

8 0
3 years ago
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