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Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Person has the flu.
- Event B: Person got the flu shot.
The percentages associated with getting the flu are:
- 20% of 30%(got the shot).
- 65% of 70%(did not get the shot).
Hence:
The probability of both having the flu and getting the shot is:
Hence, the conditional probability is:
0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
To learn more about conditional probability, you can take a look at brainly.com/question/14398287
Answer:
Step-by-step explanation:
There are
2 yellow
3 magenta
5 blue
marbles in the bag.
So total of 2 + 3 + 5 = 10 marbles
We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).
We denote P(Y1) as probability of yellow on first draw &
P(Y2) as probability of yellow on second draw
Thus,
P(Y1) = 2/10 = 1/5 [since 2 yellow and 10 total marbles]
Now,
P(Y2) = 1/9 [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]
Now, we multiply:
P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45
The probability is