Math mate problem

Please help I need the answer by 23rd (5 points).

IrinaK [193]

Answer:

The relationship between the lengths of the sides of the triangle is that they all follow the Pythagorean Theorem (at least I'm pretty sure that's the answer.

Step-by-step explanation:

If you plug in the smaller sides like 9^2+40^2 which equals to 1681. Then you square 1681, you'll get 41 as your hypotenuse. The sides of triangle provided above your question, should follow the formula given to you which is c^2=a^2+b^2. Just to be safe, you can check if all of the triangle sides actually are true for the Pythagorean theorem.

3 0

3 years ago

I'm taking a test and it's really important that I pass it because I'm already failing the class. Please help me I have no idea

soldi70 [24.7K]

Answer:

1. 15+5i

2. 3+4i

3. 3+i

4. 30

Step-by-step explanation:

4 0

3 years ago

400 passengers go on a coach trip.

Afina-wow [57]

Answer: ₹759407.56

Step-by-step explanation: Total No. of passengers = 400

1 Coach = 50 passengers

∴Total No. of coaches= 400/50=8 coaches.

Cost for each passenger= £23

∴Total cost for 400 passengers= 400x£23

= £9200 ( 1£=82.5443 ₹) ∴ Total cost for passengers = ₹759407.56

Money spent per mile= 70p

∴Money spent for 200 miles= 200x70p=14000p

(1₹=100p) thus, 14000p=₹140

Total profit= Money from the passengers- Money spent for fuel

∴₹759407.56- ₹140= ₹7,59,407.56

Actually I am a 9th grader and I have tried this question, so I am not sure for my answer, But I have tried my level best.

4 0

3 years ago

What is the rate of change between the points (-3, 0) and (-2, -5)?

Elis [28]

The rate of change is the change in Y over the change in X.

Rate of change = (-5 - 0) / (-2 - -3)

Rate of change = (-5 ) / (-2+3)

Rate of change = -5 /1

Rate of change = -5

3 0

3 years ago

Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S

Sophie [7]

Answer:

Recall that a relation is an equivalence relation if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

Reflexive: We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that $A=J^{-1}AJ$ . Thus, A↔A.

Symmetric: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that $A=P^{-1}BP$ . In this equality we can perform a right multiplication by $P^{-1}$ and obtain $AP^{-1} =P^{-1}B$ . Then, in the obtained equality we perform a left multiplication by P and get $PAP^{-1} =B$ . If we write $Q=P^{-1}$ and $Q^{-1} = P$ we have $B = Q^{-1}AQ$ . Thus, B↔A.

Transitive: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have $A=P^{-1}BP$ and from B↔C we have $B=Q^{-1}CQ$ . Now, if we substitute the last equality into the first one we get

$A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP)$ .

Recall that if P and Q are invertible, then QP is invertible and $(QP)^{-1}=P^{-1}Q^{-1}$ . So, if we denote R=QP we obtained that

$A=R^{-1}CR$ . Hence, A↔C.

Therefore, the relation is an equivalence relation.

4 0

4 years ago