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VARVARA [1.3K]
3 years ago
11

Math mate problem

Mathematics
1 answer:
eduard3 years ago
7 0
You will buy 94 cockroaches at most and 1 cockroach at least

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Solve the slope…. pls
Zielflug [23.3K]

Answer:

slope = 5/7

Step-by-step explanation:

Given the x-intercept: (-7, 0) and the y-intecept: (0, 5):

We can use the slope formula:

m = \frac{y2 - y1}{x2 - x1}

Let (x1, y1) = (-7, 0)

(x2, y2) = (0, 5)

Plug these values into the slope formula:

m = \frac{y2 - y1}{x2 - x1} = \frac{5 - 0}{0 - (-7)} = \frac{5}{7}

Therefore, the slope is 5/7

4 0
3 years ago
Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel
icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)

So, the slope is:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}

Line h passes through the following points:

(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)

So, the slope is:

m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0
3 years ago
Which is a solution for 7 (x + 2) = 35?<br><br> A. -2<br> B. 7/33<br> C. 3 <br> D. 5<br> E. 26
enot [183]

7(x+2) = 35

Use the distributive property:

7x + 14 = 35

Subtract 14 from each side:

7x = 21

Divide both sides by 7:

x = 21 / 7

X = 3


The answer is C. 3

4 0
3 years ago
Read 2 more answers
Does (3/4,radica 7/4) lie on the circumference of the unit circle
galina1969 [7]
We have (3/4)^2 + (\sqrt{7}/4)^2 = 9/16 + 7/16 = (9+7)/16 = 16/16 = 1.
The answer is yes.
3 0
3 years ago
Write the standard equation for each circle:<br> Center at (-1,6) with radius 1/3
Sunny_sXe [5.5K]
The answer is:
(X-(-1))^2 + (Y-(6))^2 = (1/3)^2

this can be simplified into the following
(X+1)^2 + (Y-6)^2 = 1/9
7 0
4 years ago
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