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natima [27]
2 years ago
13

Choose the best estimate for the length of a piece of notebook paper.

Mathematics
2 answers:
garri49 [273]2 years ago
7 0
The answer is C. 11 inches
Fynjy0 [20]2 years ago
5 0

Answer:

11 in

Step-by-step explanation:

Standard paper is 11 x 8 inches

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Jim can run a mile in 5 minutes and 50 seconds, john can run a mile in 6 minutes and 40 seconds.
QveST [7]

Jim's time is 5:50 and John's time is 6:40.

8 0
2 years ago
Lily uses 1/3 pints of milk and 2 bananas to prepare a milkshake. If she uses 2/3 pints of milk, how many bananas would she need
telo118 [61]

Answer:

4 bananas

Step-by-step explanation:

She uses 4 bananas because if 2 are needed to prepare 1/3 pints for 2 then 2/3 u need 4

8 0
2 years ago
Identify the function that contains the data in the following table:Х-20o235f(x)531224O f(x) = x/ + 1O f(x) = x - 21O f(x) = lx
kirill [66]

To identify the function that contains the data in the table, we should first visualize the data.

A graph of the data is shown below:

From the plot above, we can identify that:

The graph above is a graph of f(x) = |x|, translated to the right 2 units and translated upwards 1 unit.

Hence, the function is:

f(x)\text{  = |x-2| + 1}

Answer:

Option D

3 0
1 year ago
Math Please Hurry Im smooth brain
Klio2033 [76]

Answer:

see below

Step-by-step explanation:

1. yes

2. no, 4.82 x 10^4

3, no, 9.9 x 10^-4

4. no, 3.6 x 10^6

5. yes

6. no, 7.8 x 10^-4

6 0
2 years ago
Read 2 more answers
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
3 years ago
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