Answer:
Let "L" be the dominant allele for little finger shape and "l" be the recessive allele for the same.
It is given that a person is homozygous dominant for blood group B and little finger shape. Hence, the genotype would be
<em>LL</em>
The other person is heterozygous for blood group A and homozygous recessive for little finger shape. Hence, the genotype would be 
The type of gametes formed by the first parent would be
<em> </em>only.
The type of gametes formed by second parent would be
and <em>il.</em>
The cross is shown in the attached figure.
According to the cross, we get two phenotype:
- offspring with blood group AB and dominant little finger shape, and
- offspring with blood group group B and dominant little finger shape.
- They are present in 4 : 4 = 1 : 1
According to the cross, we get two genotype:


- They are also present in 4 : 4 = 1 : 1.
i think it is b d and or e
Answer:
After 6000 years, approximately 500 atoms of carbon-14 will be left in the femur bone of an animal which had 1000 atoms of carbon-14 when the animal died.
Explanation:
The half-life of a radioactive isotope of an element is the time taken for half the atoms present in a given amount of the element to undergo decay or disintegration. For example, the half-life of carbon-14 isotope is 5730 years. This means that, if there are 100 atoms of carbon-14 present in a given sample of a material, in the next 5730 years, approximately, 50 atoms of carbon-14 will be left in the material.
Since the half-life of radioactive isotopes are constant, these radioactive isotopes are used in the determining the ages of ancient life-forms as well as rocks.
In the given example, after 6000 years, approximately 500 atoms of carbon-14 will be left in the femur bone of an animal which had 1000 atoms of carbon-14 when the animal died.