Answer:The Rainforest mesocosm, at the north end of Biosphere 2, was created to simulate several tropical Rainforest habitats. The biome can be divided into the following habitats: Bamboo belt of dense bamboo species was intended to screen the biome from airborne salt that might be entrained from the ocean biome.
Explanation: yes
Answer:
b. A transferase deficiency will result in an accumulation of the toxic metabolite galactosse 1-phosphate.
c. A galactokinase deficiency will cause an accumulation of galactose.
Explanation:
Transferase is an enzyme which is responsible for the breakdown of galactose which is a known milk sugar. Its deficiency causes the formation of toxic materials such as galactose-1-phosphate which comes from galactose, and galactitol. Galactokinase is also an enzyme which helps in the conversion of galactose into galactose 1-phosphate with the expenditure of ATP molecule, so its deficiency causes the deposition of galactose.
Answer:
4, based on the assumption that the R allele is dominant over the r allele, and that the T allele is dominant over the t allele.
Explanation:
Any bush with a dominant petal color allele (R) will have red petals. This includes Rr and RR.
Any bush with a dominant bush size allele (T) will have a tall bush. This includes Tt and TT.
The only way to acquire a short bush or pink petals is to have two recessive alleles together (tt, rr).
RRTT, RrTT, RRTt, and RrTt -> red petals with tall bushes
RRtt, Rrtt -> Red petals with short bushes
rrTt, rrTT -> pink petals and tall bushes
rrtt-> pink petals with short bushes.
These are the four phenotype variations possible in this dihybrid cross.
Answer:
that takes place inside a plant, producing food for the plant to survive
Answer:
The Rats.
Explanation:
I think it would be the rats because its a common pest and who has chickens around their house?
