An ordered pair which makes both inequalities true is (-1, -3).
<h3>What is an ordered pair?</h3>
An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.
Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.
For ordered pair (-3, 5), we have:
y < –x + 1
5 < -(-3) + 1
5 < 3 + 1
5 < 4 (False).
For ordered pair (-2, 2), we have:
y < –x + 1
2 < -(-2) + 1
2 < 2 + 1
2 < 3 (True).
y > x
2 > -2 (True)
For ordered pair (-1, -3), we have:
y < –x + 1
-3 < -(-1) + 1
-3 < 1 + 1
-3 < 2 (True).
y > x
-3 > -1 (False)
For ordered pair (0, -1), we have:
y < –x + 1
-(-1) < -(0) + 1
1 < 1
1 < 1 (False).
y > x
-1 > 0 (False)
Read more on inequality here: brainly.com/question/27166555
#SPJ1
follow these steps:
1) y-4=7x^2
2) (y-4)/7 = x^2
so you must inverse x and y names:
Answer:
hi im going to work on this i wiil comment answer in a minute
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
i double checked
The simplified answer is 
If you are dividing powers with like terms you subtract the denominator to the numerator.
