Answer and Explanation:
As I don't have access to live butterflies, the control group would be clay models that do not exhibit warning coloration, e.g. beige / white / brown. In contrast, the experimental group would be the clay models that exhibir a strong warning coloration such as color orange / red.
After preparing the clay 'prey', I would locate them in specific places outside where birds are able to detect them. Moreover, I would use a webcam to monitor the recurrence of birds in the area.
1st experiment: Test whether birds approach the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Then, record the minutes they spent wandering near the prey.
2nd experiment: Test wheter birds feed on the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Record time.
Carry out statistical analyses.
Present results and discuss.
Answer:
plants
Explanation:
because in group of living things there is plants and animals , plants have chrolophyll and animals don't have chrolophyll
100%-9%=91%
$819/91%=$900
100%+5%=105%
$900x105%=$945
Answer: He should sell it at $945 to make a profit of 5%.
<span>protista is a producer because it is a plant</span>
The right answer is 3 nucleotide bases.
5'-CGGCACCGCCCTAAGTCTCT-3'
5'-AGGCACCGCCCTAAGTCTAC-3'
It would be necessary first to align the two sequences side by side so as to be able to compare them, and they should also be in the same direction.
The nucleotides marked in bold are the nucleotides that differ between standard and O. Kisutch.
These nucleotide changes are necessarily due to substitution mutations that exchanged one nucleotide for another in the same location.
