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nydimaria [60]
3 years ago
10

As X increase or decrease Y increase or decrease. The Function is linear or nonlinear.​

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:

linear

Step-by-step explanation:

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Help! sin^-1(tan(pi/4)
devlian [24]

Answer:

Step-by-step explanation: the best way to get this answer is by using a scientific calculator fx-991es plus I recommend

Let's go manual for now.

Let's covert pi/4 to angle

1⁰ =π/180

1 radian =180/π

Therefore π/4 × 180/π

∅ =45⁰

Sin-¹(tan 45⁰)

Tan 45⁰= 1

Sin-¹ (1) = 90⁰. Press { sin,-¹ (1) } on your calculator

Sin-¹ (tan pi/4) = 90⁰

4 0
3 years ago
Consider the function on the graph PLEASE HELP ME!!!!!!!!!!
AleksAgata [21]

Answer:-10 to positive 10

Step-by-step explanation:

i do not know if im right but i tried.. sorry

8 0
2 years ago
Jordan keeps track of rainy days for one year. This year he counted 27 weeks with at least 1 rainy day. How many weeks had no ra
Komok [63]
There are 52 weeks in a year, so subtract 27 from 52.

52-27=25

There were 25 weeks with no rainy days
3 0
4 years ago
A. Use composition to prove whether or not the functions are inverses of each other.
kogti [31]

A. In a composition of two functions the first function is evaluated, and then the second function is evaluated on the result of the first function. In other word, you are going to evaluate the second function in the first function.

Remember that you can evaluate function at any number just replacing the variable in the function with the number. For example, let's evaluate our function f(x) at x=1:

f(x)=\frac{1}{x-3}

f(1)=\frac{1}{1-3}

f(1)=\frac{1}{-2}

Similarly, to find the composition of f(x) andg(x), we are going to evaluate f(x) at g(x). In other words, we are going to replace x in f(x) with \frac{3x+1}{x}:

f(x)=\frac{1}{x-3}

f(g(x) = f(\frac{3x+1}{x} ) = \frac{1}{\frac{3x+1}{x} -3}

Remember that two functions are inverse if after simplifying their composition, we end up with just x. Let's simplify and see what happens.

f(g(x)=\frac{1}{\frac{3x+1}{x} -3}

f(g(x)=\frac{1}{\frac{3x+1-3x}{x} }

f(g(x)=\frac{1}{\frac{1}{x} }

f(g(x)=x

Now let's do the same for g(f(x)):

g(\frac{1}{x-3} )=\frac{3(\frac{1}{x-3})+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3}{x-3}+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3+x-3}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{\frac{x}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{x}{x(x-3)}

g(f(x))=\frac{x}{x(x-3)}

We can conclude that g(x) is the inverse function of f(x), but f(x) is not the inverse function of g(x).

B. The domain of a function is the set of all the possible values the independent variable can have. In other words, the domain are all the possible x-values of function.

Now, interval notation is a way to represent and interval using an ordered pair of numbers called the end points; we use brackets [ ] to indicate that the end points are included in the interval and parenthesis ( ) to indicate that they are excluded.

Notice that when x=0, g(x)=\frac{3(0)+1}{0} =\frac{0}{0}, so when x=0, g(x) is not defined; therefore we have to exclude zero from the domain of f(g(x)).

We can conclude that the domain of the composite function f(g(x)) in interval notation is (-∞,0)U(0,∞)

Now let's do the same for g(f(x)).

Notice that the composition is not defined when its denominator equals zero, so we are going to set its denominator equal to zero to find the values we should exclude from its domain:

x(x-3)=0

x=0 and x-3=0

x=0 and x=3

Know we know that we need to exclude x=0 and x=3 from the domain of g(f(x)).

We can conclude that the domain of the composition function g(f(x)) is (-∞,0)U(0,3)U(3,∞)

4 0
3 years ago
Read 2 more answers
4. Joseph is making cookies. The recipe requires 1/2 cups of flour and 1 teaspoons of sugar.
oksian1 [2.3K]

Answer:

He will use 4.

Step-by-step explanation:

1/2 flower-1 sugar*4 = 2 flower - 4 sugar

6 0
3 years ago
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