1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Galina-37 [17]
3 years ago
6

WILL GIVE A BRAINLEST FOR RIGHT ANSWER

Mathematics
2 answers:
Helen [10]3 years ago
6 0

Answer: The solids have the same types of vertical cross sections through the base are a rectangular prism and a cylinder (first option)


Solution:

a. The vertical cross section through the base of a rectangular prism is a rectangle.

b. The vertical cross section through the base of a cylinder is a rectangle.

c. The vertical cross section through the base of a cone is a triangle.

d. The vertical cross section through the base of a pyramid is a triangle.

Then:

First option is true.

Second option is false.

Third option is false.

Fourth option is false.

Vanyuwa [196]3 years ago
5 0

Answer:a rectangular prism and a cylinder

Step-by-step explanation:

You might be interested in
The functions f(x) = 2x2 + 2 and g(x) = 2X+1 + 2 are graphed on the coordinate plane as shown.
ra1l [238]

Answer:

The functions f(x) = 2x2 + 2 and g(x) = 2x+1 + 2 are graphed on the coordinate plane as shown.

Step-by-step explanation:

4 0
3 years ago
Angle α lies in quadrant II , and tan α = <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B12%7D%7B5%7D" id="TexFormula1" title="-\f
Hunter-Best [27]

Since \alpha lies in quadrant II and \beta lies in quadrant IV, we expect \sin\alpha>0, \cos\alpha, and \sin\beta.

Recall the Pythagorean identities,

\sin^2x+\cos^2x=1\iff1+\cot^2x=\csc^2x\iff\tan^2x+1=\sec^2x

It follows that

\sec\alpha=\dfrac1{\cos\alpha}=-\sqrt{\tan^2\alpha+1}=-\dfrac{13}5\implies\cos\alpha=-\dfrac5{13}

\sin\alpha=\sqrt{1-\cos^2\alpha}=\dfrac{12}{13}

\sin\beta=-\sqrt{1-\cos^2\beta}=-\dfrac45

Recall the angle sum identity for sine:

\sin(\alpha+\beta)=\sin\alpha\cos\beta+\sin\beta\cos\alpha

So we have

\sin(\alpha+\beta)=\dfrac{12}{13}\dfrac35+\left(-\dfrac45\right)\left(-\dfrac5{13}\right)=\boxed{\dfrac{56}{65}}

4 0
3 years ago
Help meeeeeeeeeeeeeeee
Orlov [11]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
If m angle ABC=180. What is the degree measure of angle ADC
Damm [24]

Answer:

if ∠ABC = 180°,

then, 2x∠ADC = ∠ABC ( angles subtended by an arc at the center is double the angle subtended it at any point on the remaining part if the circle)

{ please read the theorem carefully as i know u wont be able to understand it at first try :) }

therefore ∠ADC = 90°

4 0
4 years ago
Read 2 more answers
Tyreek and his 4 friends equally split 3cups of juice. How much juice does each person get?​
lyudmila [28]

Answer:

\frac{3}{5} or 0.6 of a cup of juice

Step-by-step explanation:

Divide 3 by 5:

3/5

= 0.6

So, each person would get \frac{3}{5} or 0.6 of a cup of juice.

5 0
3 years ago
Other questions:
  • If N has a remainder of 2 when divided by 3,4,5, or 6 and N is a 3 digit number, what is the largest possible value for N?
    12·1 answer
  • How to write an equation for the line perpendiculer and trhough the given ppoint?
    10·1 answer
  • Find the valie of x (please help
    13·1 answer
  • A group consists of 10 men and 11 women. in how many ways can a team of exactly 4 men and 6 women be selected?
    5·1 answer
  • Twenty more than half a number is 70. What is the number
    9·2 answers
  • Molly opened a bank account. She deposited $86.50 into her account every month for 20 months. She used $24.50 every month to pay
    8·1 answer
  • If x+1/x=6 then x=?????
    8·2 answers
  • Least to greatest.... help
    13·2 answers
  • The senior class of a high school needs to decide where to go for their senior trip. They have four choices: A cruise, a camping
    6·1 answer
  • Design An art class is making a mural for their school which has a triangle drawn in the middle.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!