All categories

3 years ago

Please help with this

Mathematics

2 answers:

stiv31 [10]3 years ago

7 0

Answer:

dude your teacher is on crack

Ivahew [28]3 years ago

4 0

Answer:

option B (37)

Step-by-step explanation:

74÷2 (as it's half)= 37

XT= 37

Hope it helps!

You might be interested in

Veronica is self employed. In one year, Veronica generates a gross income of $65,500. When calculating her taxes, Veronica is al

butalik [34]

Answer:

$44,850

Step-by-step explanation:

Gross income is $65,500

Allowable deductions are $2,500

Operating income is $65,500-$2,500=$63,000

From the given tax structure, Veronia will pay 15% for the first $25,000 then 30% for $63,000-$25,000=$38,000

Tax will be (0.15*$25,000)+(0.3*$38,000)=$15,150

Remaining expenses will be $5,500-$2,500=$3,000

Income after tax will be $63,000-$15,150=$47,850

Net income=$47,850-$3,000=$44,850

Ans=$44,850

7 0

3 years ago

Solve. 4 - 2x = 10 A)-7 B)-3 C)0 D)3

mars1129 [50]

Answer: The answer should be B) -3. To solve the equation you have to rewrite the equation.

4 0

3 years ago

Karissa says that to represent the expression - 7 - (- 9) on number line, she should start at 7 and move units to the IN correct

Sholpan [36]

Answer:

Step-by-step explanation:

Should start at -7 and move 9 units towards right (in the positive direction).

Should stop at 2

8 0

2 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago

Final grades are often computed using weighted averages. For example, Fran's teacher uses the following: homework 10%, quizzes 2

STALIN [3.7K]

The final grade of fran can be calculated by multiplying the corresponding percentage of his average homework, quizzes and tests, then sum it up and it is now the final grade of fran.

Final grade = (0.10 x 92) + ( 0.20 x 68) + (0.70 x 81)

Final grade = 79.5

8 0

2 years ago