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slega [8]
3 years ago
14

Jeremiah currently has an account balance of $1624.35. His initial deposit on the account was $975 and it earned 3.7% simple int

erest. How long has Jeremiah held the account
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Current Account Balance = $1,624.35

Initial Deposit = $975

Interest Rate (Simple) = 3.7% simple interest

Interest Earned = Current Account Balance - Initial Deposit

⇒ Interest Earned = $1,624.35 - $975

⇒ Interest Earned = $649.35

Now the Formula for Simple Interest is:

Simple Interest = ×\frac{\text{P x R x T}}{100}, where P is the initial deposit, R is the rate of interest and T is the time period

⇒ 649.35 = \frac{\text{975 x 3.7 x T}}{100}

⇒ T = \frac{\text{649.35 x 100}}{\text{975 x 3.7}}

⇒ T = 18

Hence, Jeremiah has had the account for 18 years.

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8 0
3 years ago
When the width of a rectangle with a length of 3/5 foot was decreased by 1/3 foot, the area of the rectangle became 7/25. Find t
insens350 [35]

Answer:

\large\boxed{\text{The original width}\ =\dfrac{4}{5}\ ft}

Step-by-step explanation:

\text{The dimensions of rectangle:}\ \dfrac{3}{5}\times w.\\\\\text{The dimensions of new rectangel:}\ \dfrac{3}{5}\times\left(w-\dfrac{1}{3}\right)\\\\\text{The area of the new rectangle:}\ A=\dfrac{7}{25}\ ft^2\\\\\text{We have the equation:}\\\\\dfrac{3}{5}\left(w-\dfrac{1}{3}\right)=\dfrac{7}{25}\qquad\text{multiply both sides by 25}\\\\25\!\!\!\!\!\diagup^5\cdot\dfrac{3}{5\!\!\!\!\diagup_1}\left(w-\dfrac{1}{3}\right)=25\!\!\!\!\!\diagup^1\cdot\dfrac{7}{25\!\!\!\!\!\diagup_1}

15\left(w-\dfrac{1}{3}\right)=7\qquad\text{use the distributive property}\\\\15w-15\!\!\!\!\!\diagup^5\cdot\dfrac{1}{3\!\!\!\!\diagup_1}=7\\\\15w-5=7\qquad\text{add 5 to both sides}\\\\15w=12\qquad\text{divide both sides by 15}\\\\w=\dfrac{12:3}{15:3}\\\\w=\dfrac{4}{5}

5 0
3 years ago
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul
Step2247 [10]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 6}}\quad ,&{{ 5}})\quad 
%  (c,d)
B&({{ x}}\quad ,&{{y}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\textit{if the distance \underline{d} is 5, then }5=\sqrt{(x-6)^2+(y-5)^2}
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4 years ago
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m_a_m_a [10]

Using the box plots given:

1. Median for 6th graders = 2.5; 4th graders = 1.5

2. Difference of spread = 1

3. Variability for 6th graders = 1.9; 4th graders = 1

4. TRUE, TRUE, FALSE, TRUE

5. C.

<h3>What is the Five-number Summary Displayed by a Box Plot?</h3>

In a typical box plot as shown in the image attached below, the five-number summary that a box plot displays include min and max values, lower and upper quartiles, and the median.

The spread = the range = max value - min value

The variability = IQR = Q3 - Q1.

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2. Spread for 6th graders = 4 - 0 = 4

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3. Variability for 6th graders (IQR) = 3.4 - 1.5 = 1.9

Variability for 4th graders (IQR) = 2 -1 = 1

4. TRUE, Q3 for 4th graders < Q3 for 4th graders

TRUE, Q1 for 6th graders = median for 4th graders

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TRUE, both grades have at least 1 students who do not participate.

5. C. Max for April = median for March.

Learn more about the box plot on:

brainly.com/question/14277132

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Step-by-step explanation:

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