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Anuta_ua [19.1K]
3 years ago
11

Plz help me thanksssss

SAT
1 answer:
Sladkaya [172]3 years ago
3 0
The correct answer is A. X<3
Please let me know if is right.
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A study of the amount of time it takes a mechanic to rebuild the transmission for a 2010 Chevrolet Colorado shows that the mean
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Answer:

The answer is 0.9599.

Explanation:

mu (sample) = mu = 8.4

s.d. (sample) = 1.8/ sq. rt. 40

P( greater than 8.1) = (8.9-8.4)/(1.8/ sq. rt. 40)

Let x be the mean time for the 40 mechanics

Standardize the mechanics: (8.9-8.4)/(1.8/ sq. rt. 40) = 1.75 = Z

P( x > 8.9) = P(Z > 1.75), this means the area to the right of Z = 1.75.

Then you need to look in the table of the Normal distribution, Z(1.75) =0.9599

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During last year's basketball season, Jackson attempted
OLga [1]

This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

150 free throws of which he made

120. So far this season, he's attempted 24 and made 16. A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted. Assuming calculations began with the start of last year's season, which of the following best approximates Jackson's overall free-throw percentage to date?

A. 67%

B. 73%

C. 78%

D. 80%

Answer:

B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

150 free throws of which he made

120

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

= 80%

This season, he's attempted 24 and made 16

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (16÷24) × 100

= 66.67%

Approximately = 67%

The best approximation for Jackson's overall free-throw percentage to date is

(Percent Free Throw for last season + Percent Free Throw for this season) ÷ 2

Percent Free Throw for last season

= 80%

Percent Free Throw for this season = 66.67%

Therefore, (80% + 66.67%) ÷ 2

= 146.67% ÷ 2

= 73.335%

Approximately = 73%

Therefore, Jackson's overall free-throw percentage to date is 73%

6 0
3 years ago
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