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Lelu [443]
3 years ago
8

List the guidelines to be followed in Shrinking of Cotton and linen.​

SAT
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

Synthetics. Polyester, nylon, spandex, acrylic, and acetate won't shrink and will resist water-based stains. Most produce static and may permanently wrinkle in a hot dryer, so dry on low.

You might be interested in
Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM
Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

<em>#include <cmath></em>

<em>#include "pppm_tip4p.h"</em>

<em>#include "atom.h"</em>

<em>#include "domain.h"</em>

<em>#include "force.h"</em>

<em>#include "memory.h"</em>

<em>#include "error.h"</em>

<em>#include "math_const.h"</em>

<em />

<em>using namespace LAMMPS_NS;</em>

<em>using namespace MathConst;</em>

<em />

<em>#define OFFSET 16384</em>

<em />

<em>#ifdef FFT_SINGLE</em>

<em>#define ZEROF 0.0f</em>

<em>#define ONEF  1.0f</em>

<em>#else</em>

<em>#define ZEROF 0.0</em>

<em>#define ONEF  1.0</em>

<em>#endif</em>

<em />

<em>void PPPMTIP4P::init()</em>

<em>{</em>

<em>  // TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms</em>

<em />

<em>  if (force->newton == 0)</em>

<em>    error->all(FLERR,"Kspace style pppm/tip4p requires newton on");</em>

<em />

<em>  PPPM::init();</em>

<em>}</em>

<em />

<em>void PPPMTIP4P::particle_map()</em>

<em>{</em>

<em>  int nx,ny,nz,iH1,iH2;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))</em>

<em>    error->one(FLERR,"Non-numeric box dimensions - simulation unstable");</em>

<em />

<em>  int flag = 0;</em>

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;</em>

<em>    ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;</em>

<em>    nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;</em>

<em />

<em>    part2grid[i][0] = nx;</em>

<em>    part2grid[i][1] = ny;</em>

<em>    part2grid[i][2] = nz;</em>

<em />

<em>    if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||</em>

<em>        ny+nlower < nylo_out || ny+nupper > nyhi_out ||</em>

<em>        nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;</em>

<em>  }</em>

<em />

<em>  int flag_all;</em>

<em>  MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);</em>

<em>  if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");</em>

<em>}</em>

<em>void PPPMTIP4P::make_rho()</em>

<em>{</em>

<em>  int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;</em>

<em>  FFT_SCALAR dx,dy,dz,x0,y0,z0;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];</em>

<em>  for (i = 0; i < ngrid; i++) vec[i] = ZEROF;</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double *q = atom->q;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = part2grid[i][0];</em>

<em>    ny = part2grid[i][1];</em>

<em>    nz = part2grid[i][2];</em>

<em>    dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;</em>

<em>    dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;</em>

<em>    dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;</em>

<em />

<em>    compute_rho1d(dx,dy,dz);</em>

<em />

<em>    z0 = delvolinv * q[i];</em>

<em>    for (n = nlower; n <= nupper; n++) {</em>

<em>      mz = n+nz;</em>

<em>      y0 = z0*rho1d[2][n];</em>

<em>      for (m = nlower; m <= nupper; m++) {</em>

<em>        my = m+ny;</em>

<em>        x0 = y0*rho1d[1][m];</em>

<em>        for (l = nlower; l <= nupper; l++) {</em>

<em>          mx = l+nx;</em>

<em>          density_brick[mz][my][mx] += x0*rho1d[0][l];</em>

<em>        }</em>

<em>      }</em>

<em>    }</em>

<em>  }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

6 0
2 years ago
Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.04 and a standard deviation of 1.52.
Pani-rosa [81]

Answer:

0.15 % of American women have a shoe size greater than 12.6

Explanation:

*See the attached photo.

7 0
3 years ago
Según el 1 of 1, la función (show) comienza a las 8 de la noche.
DaniilM [7]

According to the context of the sentence, for it to be complete and make sense we must add the missing word as it follows:

  • Según el <u>cártel</u>, la función comienza a las 8 de la noche.
  • <em>Translation</em>: According to the <u>poster</u>, the show begins at 8 at night.

A poster refers to a sheet that presents some type of information that is intended to be disseminated.

  • It captures the attention of the viewer, forcing him to perceive the message, his function to announce an event and disseminate information.

  • In the sentence, the <em>''</em><em>cártel</em><em>''</em> complies with informing the spectators of the start time of the show.

Therefore, we can conclude that the correct missing word in the sentence is<em> cártel (post)</em>, which is planned to give certain information about the show.

Learn more about Spanish here: brainly.com/app/profile/16429823

5 0
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What protection can diver's suit gear provide? what deep ocean problem can the suit not solve
____ [38]

Answer:

It keeps the body warm, protects it from physical hazards, and even increases the body’s buoyancy. One issue a diver's suit can not solve is water pressure

Explanation:

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Charlie likes to go to a local amusement park with friends a couple of times per year, but worries that he may
Anvisha [2.4K]

C. because if he only has $150 with him he can't spend more than $150 dollars.

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