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mojhsa [17]
3 years ago
7

27. Solve for x? A 25 B 16 C 27 D 9

Mathematics
1 answer:
musickatia [10]3 years ago
8 0
I’m not really sure but if I did it correctly I’m pretty sure it’s c.27
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Can someone help me plz someone help me plz help me someone as soon as possible plz someone ASAP plz ASAP
MissTica
C and D are your correct answers.
I hope this helps
8 0
3 years ago
What is 8 3/4 ÷ 2 7/8 (show ur work)
xxMikexx [17]

Answer:

<em><u>see</u></em><em><u> </u></em><em><u>below</u></em><em><u>:</u></em><em><u>-</u></em>

Step-by-step explanation:

\displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8}  }

  • Convert the mixed fractions into improper fractions.

\displaystyle{ \frac{8 \times 4 + 3}{4} \div  \frac{8 \times 2 + 7}{8}  }

\displaystyle{ \frac{32 + 3}{4}  \div  \frac{16 + 7}{8} }

\displaystyle{ \frac{35}{4} \div  \frac{23}{8}  }

\displaystyle{ \frac{35}{4}  \times  \frac{8}{23} }

\displaystyle{ \frac{35}{ \cancel4}  \times  \frac{ \cancel8 {}^{2} }{23} }

\displaystyle{ \frac{35  \times 2}{23} }

\displaystyle{ \frac{70}{23} }

\displaystyle{3 \frac{1}{23} }

6 0
2 years ago
Read 2 more answers
Please Help! Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined,
Licemer1 [7]

Answer:

<u>Given:</u>

  • g(t) = 5t² − 8t + 3

Find the following

<u>g(2)</u>

  • g(2) = 5(2²) - 8(2) + 3 = 20 - 16 + 3 = 7

<u>g(t - 2) </u>

  • g(t - 2) = 5(t - 2)² - 8(t - 2) + 3 = 5t² - 20t + 20 - 8t + 16 + 3 = 5t² - 28t + 39

<u>g(t) - g(2)</u>

  • g(t) - g(2) = 5t² − 8t + 3 - 7 = 5t² − 8t - 4
3 0
3 years ago
Read 2 more answers
Tengo ___ . Necesito agua.
melamori03 [73]

Answer:

<em>sed</em>

Step-by-step explanation:

Hope this helps!!!

6 0
3 years ago
Read 2 more answers
URGENT PLZZZ HELP
viktelen [127]

The area of the shaded portion = 100.48 cm²

Solution:

Radius of the inner circle = 2 cm

Radius of the outer circle = 6 cm

Area of the inner circle = \pi r^2

                                      =3.14 \times 2^2

Area of the inner circle = 12.56 cm²

Area of the outer circle = \pi R^2

                                      =3.14 \times 6^2

Area of the outer circle = 113.04 cm²

Area of the shaded portion = Area of the outer circle – Area of the inner circle

                                      = 113.04 cm² – 12.56 cm²

                                      = 100.48 cm²

Hence the area of the shaded portion = 100.48 cm²

4 0
3 years ago
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