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ikadub [295]
3 years ago
10

Can someone help with this to?

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

6 x

Step-by-step explanation:

because 1 times 6 then 2 then 3 and so on

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Number 16 plz I need help
andre [41]
I think it's 2.3 Because 9.66 (in total miles) divided by 4.2 (miles she hikes per hour)
8 0
3 years ago
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Find the area bounded by the given curves: <br> y=2x−x2,y=2x−4
Andrej [43]

Answer:

A = [\frac{32}{3}]

Step-by-step explanation:

Given

y_1 = 2x - x^2

y_2 = 2x - 4

Required

Determine the area bounded by the curves

First, we need to determine their points of intersection

2x - x^2 = 2x - 4

Subtract 2x from both sides

-x^2 = -4

Multiply through by -1

x^2 = 4

Take square root of both sides

x = 2   or    x = -2

This Area is then calculated as thus

A = \int\limits^a_b {[y_1 - y_2]} \, dx

<em>Where a = 2 and b = -2</em>

Substitute values for y_1 and y_2

A = \int\limits^a_b {(2x - x^2) - (2x - 4)} \, dx

Open Brackets

A = \int\limits^a_b {2x - x^2 - 2x + 4} \, dx

Collect Like Terms

A = \int\limits^a_b {2x - 2x- x^2  + 4} \, dx

A = \int\limits^a_b {- x^2  + 4} \, dx

Integrate

A = [-\frac{x^{3}}{3} +4x](2,-2)

A = [-\frac{2^{3}}{3} +4(2)] - [-\frac{-2^{3}}{3} +4(-2)]

A = [-\frac{8}{3} +8] - [-\frac{-8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8-24}{3}]

A = [\frac{16}{3}] - [\frac{-16}{3}]

A = [\frac{16}{3}] + [\frac{16}{3}]

A = [\frac{16 + 16}{3}]

A = [\frac{32}{3}]

Hence, the Area is:

A = [\frac{32}{3}]

7 0
4 years ago
What is the algebric expression of z is greater than y by ten
stiv31 [10]
Z = y + 10

I’m not sure if this is the equation you are looking for, but saying that “Z” is equal to “y + 10” is like saying that “Z” is greater than “y” by ten.

I hope this helped! ☻
3 0
3 years ago
PLZ help 50 pts. and brainliest
olganol [36]

Answer:

what do u want us to do?

Step-by-step explanation:

6 0
3 years ago
Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo
svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

PV = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}}    \end {bmatrix}

128000 = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

PV= 921.433 \begin {bmatrix}  \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

PV = $121718.2714

C) In order to estimate how many payments of $1400  it will take to pay off the loan, we have:

121718.2714 =  \begin {bmatrix}  \dfrac{1300  (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}}    \end {bmatrix}

121718.2714 = 200000  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

\dfrac{121718.2714}{200000 } =  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

0.60859 =  \begin {bmatrix}  (1 - \dfrac{12}{12.078}))^{nt}   \end {bmatrix}

0.60859 = (0.006458)^{nt}

nt = \dfrac{0.60859}{0.006458}

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88  - 177795.38

The amount of interest saved = $153920.5

6 0
4 years ago
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