$3,500(4.3%)4= $602
His new account balance after interest is $602
Answer:
The street light is 20 feet tall.
Step-by-step explanation:
This question depends on a proportion. Keep your height of the object in one ratio and the length of the shadow in the other.
25/x = 75/60 Notice the height of the structure is on the left. The length of the shadow is on the right. Cross multiply
75x = 60 * 25 Combine the right
75x = 1500 Divide by 75
x = 1500/75
x = 20
The street light is 20 feet tall.
First get the factors of 24: 2*2*2*3Then the factors of 9: 3*3 Comparing the factors, the GCF is 3 Then you can rewrite the expression: 3*8 + 3*3 At this point, I'm not sure whether what you mean is really distributive property or not since this case is more of a factoring. 3*(8+3)
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Define the numbers
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Let the first even number be x
1st even number = x
2nd even number = x + 2
3rd even number = x + 4
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Form the equation and solve
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x + x + 2 + x + 4 = -6
3x + 6 = -6
3x = - 12
x = -4
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Find the numbers
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1st even number = x = -4
2nd even number = x + 2 = -4 + 2 = -2
3rd even number = x + 4 = -4 + 4 = 0
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Answers: The numbers are -4, -2 and 0
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Answer:
see below
Step-by-step explanation:
To find the coordinates of the midpoints, add the x's and divide by 2 and add the y's and divide by 2.
The coordinates of D, the midpoint of AB, (1+3)/2 will be the x-coordinate and (4+0)/2 will be the y-coordinate.
D (2,2)
You could also see this on a graph, see image.
E, the midpoint of AC has the x-coordinate (1+-3)/2, which is -1 and y-coordinate (4+-2)/2 which is 1.
E is (-1,1)
Then we are able to calculate the slope of DE and BC.
To calculate slope, subtract the y's and put that on top of a fraction and subtract x's and put that on the bottom of a fraction. If the slopes are the same the segment are parallel.
Slope of DE:
(2-1)/(2--1)
= 1/3
Slope of BC:
(0--2)/(3--3)
=2/6
=1/3
The slopes of BC and DE are equal, so the segments are parallel.
(Alternatively, you could show that Triangle ABC and Triangle ADE are similar. Then find the segments parallel because corresponding angles are congruent.)
