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3 years ago

PLZ help 50 pts. and brainliest

Mathematics

1 answer:

olganol [36]3 years ago

6 0

Answer:

what do u want us to do?

Step-by-step explanation:

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Please help me to get an answer thanks

I am Lyosha [343]

Answer:

A=P(1+in)

A=13000(1+6/100×9)

A=press calculator

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2 years ago

Can anyone help me with these question

Kazeer [188]

So hmm notice the picture below

a)

the center of the circle is the midpoint of those two folks

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -10}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{4-10}{2}\quad ,\quad \cfrac{6-2}{2} \right)\impliedby \textit{center of the circle}$

b)

the diameter is the distance between P and Q, or the length of that segment, and the radius is half the diameter

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -10}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 6}})
\end{array}\quad 
% distance value
d = \sqrt{({{ 4}}-{{ (-10)}})^2 + ({{ 6}}-{{ (-2)}})^2}
\\\\\\
d=\cfrac{\sqrt{(4+10)^2+(6+2)^2}}{2}\impliedby \textit{radius of the circle}$

c)

so, from a), you found the h,k coordinates for the center, from b) you've got the radius

so, just plug them in here then $\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}$

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3 years ago

What is the sale price of an item that was originally $95 with a 35%<br> discount?

jasenka [17]

Answer:

$61.75

Step-by-step explanation:

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3 years ago

Read 2 more answers

How to write 208,561 in expanded form

emmasim [6.3K]

200,000+8,000+500+60+1. Expanded form

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4 years ago

Read 2 more answers

What are the actual roots of 2x^2+2x-24

Reptile [31]

Answer:

The roots are 3 and -4

Step-by-step explanation:

Well the roots of a polynomial are when that polynomial is set to zero. So this becomes $2x^{2} +2x-24=0$ . Dividing by two on both sides we get $x^{2}+x-12=0$ . Then, by factoring we get $(x+4)(x-3)=0$ . Then, since one of them has to be zero, we get two equations: $(x+4)=0$ and $(x-3)=0$ . Solving we get $x=-4$ and $x=3$ .

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3 years ago