∠KMN = (1/2)*arc KN . . . . . . this relationship is true of any inscribed angle. (It is a useful relationship to remember.)
= 95°/2
= 47.5°
Answers:
u = 18
v = 20
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Work Shown:
The leg YZ is congruent to the left FH
This means YZ = FH and that leads to u+v-18 = 10u-8v
The hypotenuse ZX is congruent to the hypotenuse HG
This means ZX = HG and we get the equation 14v-14u+32 = v+u+22
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The system of equations we have so far is
u+v-18 = 10u-8v
14v-14u+32 = v+u+22
Let's get the equations into standard form
Start with the first equation
u+v-18 = 10u-8v
u+v = 10u-8v+18
u+v-10u+8v = 18
-9u+9v = 18
-9(u-v) = 18
u-v = 18/(-9)
u-v = -2
Note how we can solve for the variable u to get
u = v-2
which we'll use later
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Let's get the other equation into standard form as well
14v-14u+32 = v+u+22
14v-14u-v-u = 22-32
-15u+13v = -10
Now plug in u = v-2 and solve for v
-15u+13v = -10
-15(v-2) + 13v = -10
-15v+30+13v = -10
-2v+30 = -10
-2v = -10-30
-2v = -40
v = -40/(-2)
v = 20
Which means,
u = v-2
u = 20-2
u = 18
Answer:
79°
Step-by-step explanation:
Angle one is an alternate exterior angle to the angle that has 79° in it so angle one will equal 79°.
notice, it was pawned for only 1 month, so the "yearly" rate is for 1 month, which is 1/12 of the year, since a year has 12 moths
you'll get a rate in decimal terms, to get the % amount, just multiply it times 100
