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3 years ago

What’s the answer (question to much to type).

Mathematics

1 answer:

ElenaW [278]3 years ago

6 0

What is the decimal to this fraction

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Help find the answer for problem number 4

Olin [163]

Adult ticket (a) = $5
Child ticket (c) = $2

785 tickets = $3280

a + c = 785 tickets
5a + 2c = $3280

c = 215 child tickets
a = 570 adult tickets

570 + 215 = 785 tickets
5(570) + 2(215) = $3280

There were 215 child tickets sold on Saturday

3 0

3 years ago

The length and breadth of a rectangular shaped plot is 1215 m and 527 m respectively. Find its perimeter.

ss7ja [257]

Answer:

3484m

Step-by-step explanation:

Add 1215(2) and 527(2) together

4 0

3 years ago

Read 2 more answers

The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c)

Ilya [14]

Answer:

$\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29$

$s=1.09$

Step-by-step explanation:

For this case we have the following data given:

2.3 3.1 2.8

1.7 0.9 4.0

2.1 1.2 3.6

0.2 2.4 3.2

Since the data are assumedn normally distributed we can find the standard deviation with the following formula:

$\sigma =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And we need to find the mean first with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29$

And then we can calculate the deviation and we got:

$s=1.09$

7 0

3 years ago

Read 2 more answers

Find the total number of unit cubes that fill the entire prism.<br>unit cubes<br>DONE

zloy xaker [14]

Answer:

(6 × 3 × 4) 72

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

At a carnival, contestants are asked to keep rolling a pair of dice until they roll snake eyes. The number of rolls needed has a

Stells [14]

Answer:

The two numbers of rolls are 25.2 and 46.8.

Step-by-step explanation:

The Chebyshev's theorem states that, if X is a r.v. with mean µ and standard deviation σ, then for any positive number k, we have

$P (|X -\mu| < k\sigma) \geq (1-\frac{1}{k^{2}})$

Here

$(1-\frac{1}{k^{2}})=0.75\\\\\Rightarrow \frac{1}{k^{2}}=0.25\\\\\Rightarrow k=\sqrt{\frac{1}{0.25}}\\\\\Rightarrow k=2$

Then we know that,

$|X - \mu| \geq k\sigma,\\\\ \Rightarrow \mu - k\sigma \leq X \leq \mu + k\sigma$ .

Here it is given that mean (µ) = 36 and standard deviation (σ) = 5.4.

Compute the two values between which at least 75% of the contestants lie as follows:

$P(\mu - k\sigma \leq X \leq \mu + k\sigma)=0.75\\\\P(36 - 2\cdot\ 5.4 \leq X \leq 36 + 2\cdot\ 5.4)=0.75\\\\P(25.2\leq X\leq 46.8)=0.75$

Thus, the two numbers of rolls are 25.2 and 46.8.

8 0

3 years ago