We have been given that a 208-yard-long road is divided into 16 parts of equal length.
Let us find length of each part.
Length of each part will be 13 yards.
We are told that Mr. Ward paints a 4-yard-long strip in each part.
Now we will subtract length of painted strip from length of each equal part to find length of unpainted strip of each part of the road.
Therefore, length of each unpainted strip will be 9 yards.
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
940.8 N
1254.4 N
Step-by-step explanation:
I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:
On the top:
F = pressure * area
P = density * gravity * height
the height would be:
1m - 0.4m = 0.6m
replacing:
P = 1000 * 9.8 * 0.6 = 5880
A = (0.4) ^ 2 = 0.16
F = 5880 * 0.16
F = 940.8 N
On the sides:
dF = d * g * h * dA
dA = 0.4 * dh replacing
dF = 1000 * 9.8 * h * 0.4 * dh
dF = 3920 * h * dh
We integrate both sides and we have:
F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1
F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)
F = 1254.4 N
Answer:
y = 2x + 2
Step-by-step explanation:
To find the slope we do (Y1 - Y2)/(X1-X2) aka rise over run
So, m = (-4 - 2) / (-3 - 0)
m = 2
Now we have y = 2x +b
Notice one of our points is (0,2)
Since the x value of that point is 0, it is the y intercept.
In the slope intercept form b = y-intercept
Therefore b = 2
So, y = 2x + 2
Step-by-step explanation:
i think the first equation is for the first graph because the inside of the absolute can't be negative and the second is for the second graph. i hope i helped
