26) Let f(x)=x4−1x2−1 for x≠−1,1 .
a. Sketch the graph of f .
b. Is it possible to find values k1 and k2 such that f(−1)=k and f(1)=k2 , and that makes f(x) continuous for all real numbers? Briefly explain.
27) Sketch the graph of the function y=f(x) with properties i. through vii.
i. The domain of f is ( −∞,+∞ ).
ii. f has an infinite discontinuity at x=−6 .
iii. f(−6)=3
iv. limx→−3−f(x)=limx→−3+f(x)=2
v. f(−3)=3
vi. f is left continuous but not right continuous at x=3 .
vii. limx→−∞f(x)=−∞ and limx→+∞f(x)=+∞
Answer:
y=1/6x+13/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(5-4)/(4-(-2))
m=1/(4+2)
m=1/6
y-y1=m(x-x1)
y-4=1/6(x-(-2))
y-4=1/6(x+2)
y=1/6x+2/6+4
y=1/6x+1/3+4
y=1/6x+1/3+12/3
y=1/6x+13/3
Answer:
answer
Step-by-step explanation:
The formula for simple annual interest is:
I = Prt
where,
I = Interest accumulated = $910.90
P = Principal Amount = $62000
r = Interest rate = 9.4% = 0.094
t = time in years
Using the values in above equation, we get:
910.90 = 62000 x 0.094 x t
⇒ t = 910.90/(62000 x 0.094) = 0.156
This is the time in years. Since there are 365 days in a year, the time in days will be:
t = 0.156 x 365 = 57 (rounded to nearest day)
This means, Nate kept the borrowed money for 57 days