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Galina-37 [17]
3 years ago
11

Given 8 students 3 of which are females if 2 students are selected at random without replacement what is the probability that bo

th students are female?
Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0
3/8

37.5% that they will be fremale
Sedaia [141]3 years ago
4 0
P(1th fem)=3/8
p(2th fem)=2/7
so p(1&2 fem)=3/8.2/7=3/28
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Sam's closet contains blue and green shirts. He has eight blue shirts, and seven green shirts. Five of the blue shirts have stri
Bas_tet [7]

Answer:  The answer is 80%.


Step-by-step explanation:  Let us define the following events.

B = the event that the shirt is blue,

G = the event that the shirt is green

and

S = the event that the shirt is striped.

So, n(B) = 8,  n(G) = 7,  n(B and S) = 5, n(G and S) = 4.

n(S) = 5 + 4 = 9.

We have

n(B\cup S)=n(B)+n(S)-n(B\cap S)=8+9-5=12.

Therefore, the required probability is

p=\dfrac{n(B\cup S)}{8+7}=\dfrac{12}{15}=\dfrac{4}{5}=0.8=80\%.

Thus, the answer is 80%.


3 0
2 years ago
Can you please solve this equation?
zmey [24]

x = -52 4/17
 the full answer in attachments

3 0
3 years ago
Does the relation {(-5, -3), (7,2), (3,8), (3, -8)} represent a function. Use the arrow digram. Then explain your answer.
Maslowich
No it is not a function
4 0
2 years ago
According to the rational root theorem, which is a factor of the polynomial f(x)=3x^3-5x^2-12x+20?
MakcuM [25]

Answer:

(x-2), (x+2), (3x-5)

Step-by-step explanation:

Factors of 3: ±1, ±3

Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20

Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)

Pick a number to divide the polynomial by (I picked 2)

(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10

So (x-2) is a factor of f(x) = 3x³-5x²-12x+20

Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20

4 0
2 years ago
Simplify the expression: 2(4 + 6j)
aniked [119]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

Step-by-step explanation:

\sf{2(4 + 6j)}

Distribute 2 through the parentheses

\longrightarrow{ \sf{2 \times 4  + 2 \times 6j}}

\longrightarrow{ \sf{8  + 12j}}

Hope I helped!

Best regards! :D

8 0
3 years ago
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