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anyanavicka [17]
3 years ago
7

A runner finished his marathon in 180 minutes. A marathon is around 26 miles.

Mathematics
2 answers:
mash [69]3 years ago
7 0

Answer:

I'd say 6.9 paces per mile.

Step-by-step explanation:

pashok25 [27]3 years ago
6 0
6.9 is his pace i believe
You might be interested in
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
2 years ago
Evaluate the expression. r = , v = , w = v ⋅ w
FromTheMoon [43]

Answer:

v . w= -13

Step-by-step explanation:

Evaluate the expression: v ⋅ w Given the vectors: r = <8, 1, -6>; v = <6, 7, -3>; w = <-7, 5, 2>

Solution

Given the vectors:

r = <8, 1, -6>

v = <6, 7, -3>

w = <-7, 5, 2>

If you're asking about the dot product.

The dot product is a scalar. It is the sum of the product of the corresponding components.

v.w = (6*-7) + (7*5) + (-3*2)

= -42+35-6

= -13.

6 0
3 years ago
Hector serves ice cream at a local ice cream shop. he sells 19 ice cream cones on sunday,27 ice cream cones on sunday, and 153ic
labwork [276]
So, what you want to do here is subtract the ice cream sold on the weekend from the ice cream that was sold during the rest of the week.
He sold 19 on Saturday and 27 on Sunday, so these numbers need to be subracted from your total for the week.

(Total Sold) - [(Amount sold Saturday) + (Amount sold Sunday)] = (Amount sold on weekdays)

153 - (19 + 27) = X
153 - 46 = X
107 = X
3 0
3 years ago
PLEASE HELP
notsponge [240]

Answer:

(a)

x cubed is

=x^3=x3

5 times the cube of x is

=5x^3=5x3

4 times x is

=4x=4x

the quotient of 4 times x and 3 is

=\frac{4x}{3}=34x

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}=5x3−34x ..........Answer

(b)

5 times cube of x is

=5x^3=5x3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}=4x5x3 ..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4=5x3−4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}=x5x3−4 ...........Answer

(d)

difference of 5 times x and 4 is

=5x-4=5x−4

so,

the cube of the difference of 5 times x and 4 is is

=(5x-4)^3=(5x−4)3 ............Answer

5 0
2 years ago
Simplest form for 16/56
VARVARA [1.3K]
The answer is 2/7 because you're finding the greatest common factor of both numbers. The gcf is 8, so divide both by 8 and you'll get 2/7
4 0
2 years ago
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