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DENIUS [597]
4 years ago
13

There is a $81,818 loan with annual interest due. There was $900 in closing fees and $6,300 in total interest the first year. If

the APR is the finance charge (interest plus fees) for one year ÷ amount financed, what was the APR for that year?
Mathematics
2 answers:
Marysya12 [62]4 years ago
7 0
The APR for that year was 8.8%. The APR was calculated with the formula above in the question (interest+fees)/principal of the loan resulting in 8.8%. The Annual Percentage Rate is used by financial institutions to assess a debtor's ability to pay when that debtor wants to take a new mortgage loan for assessing the risk of unpaid debt.
statuscvo [17]4 years ago
6 0

Answer:

8.8

Step-by-step explanation:

odyssey ware

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Does the budgeted amount cover the actual amount for expenses, savings, and emergencies? a) no, it's short $207.00. b) no, it's
Korvikt [17]

The expense amount is more than the savings amount. No, it's short $207 then the correct option is A.

<h3>What are statistics?</h3>

Statistics is the study of collection, analysis, interpretation, and presentation of data or to discipline to collect, and summarise the data.

From the table, we have

The amount of the savings will be

Saving amount = $ 20

Then the amount of the expense will be

Expense amount = 150 + 75 + 2 = 227

Then the budgeted amount covers the actual amount for expenses, savings, and emergencies will be

→ savings amount - expense amount

→ 20 - 227

→ $ 207

Thus, the expense amount is more than the savings amount. No, it's short $207.

More about the statistics link is given below.

brainly.com/question/10951564

7 0
2 years ago
the arlington drama club is selling tickets to an upcoming play. They can sell at most 250 tickets. The adult tickets for $15 ea
allochka39001 [22]

Number of adult tickets = 75

Number of student tickets = 175

Solution:

Let x represents the number of adult tickets and

y represents the number of student tickets.

Total number of tickets sold = 250

⇒ x + y = 250 – – – – (1)

Cost of adult ticket = $15

Cost of student ticket = $5

Total cost of collection = $2000

15x + 5y = 2000 – – – – (2)

Multiply equation (1) by 5

⇒ (1) × 5  5x + 5y = 1250 – – – – (3)

Subtract equation (3) from equation (2), we get

15x + 5y – 5x – 5y = 2000 – 1250

⇒ 10x = 750

⇒ x = 75

Substitute x = 75 in equation (1), we get

⇒ 75 + y = 250

⇒ y = 250 – 75

⇒ y = 175

Number of adult tickets = 75

Number of student tickets = 175

6 0
3 years ago
Which ordered pair is a solution to the linear inequality?
svet-max [94.6K]

Answer:

b

Step-by-step explanation:


5 0
4 years ago
Algebra 2A Help !<br><br> Tadakimasu ~
Ludmilka [50]
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)

first factor into (x-r1)(x-r2)... form

p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)

multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2 

so

p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real

baseically

(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1

7 0
3 years ago
Draw a quick picture for 37 . Draw to show how you would subtract 19 from 37 write to explain what you did
Alik [6]
Draw 37 circles and then use / slashes and cross out 19 of those circles
6 0
3 years ago
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