Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
It doesn’t bother me that much but it’s understandable
Answer:
simplify =36x−24y
factor =12(3x−2y)
Step-by-step explanation:
Let's simplify step-by-step.
4(5x−6y)+16x
Factor 4(5x−6y)+16x
36x−24y
Answer:
The investment at the end of the period will be $584.89.
Step-by-step explanation:
FV = PV e⁽ⁿˣ⁾
FV = Future Value = ?
PV = Present Value = $396
n = Interest Rate = 13%
x = time in years = 3
e = mathematical constant = 2.7183
FV = 396 x 2.7183⁽⁰°¹³ ˣ ³⁾
FV = 396 x 1.4770
FV = $584.89