Answer:
-2/3
Step-by-step explanation:
Log125(1/25)=x
Raise each side to the base of 125
125^Log125(1/25)=125^x
1/25 = 125^x
Rewrite 25 as a power of 5 and 125 as a power of 5
1 / 5^2 = 5^3^x
The if power is in the denominator, we can bring it to the numerator by making it negative
5^-2 = 5^3^x
We know that a^b^c = a^(b*c)
5^-2 = 5^(3*x)
Since the bases are the same, the exponents are the same
-2 = 3x
Divide by 3
-2/3 = 3x/3
-2/3 =x
If he ran 35 meters in 10 seconds, how many meters did he run in a second?
35m=10s
? =1
1/10*35m=3.5m
Therefore he ran 3.5 meters in a second.
Answer:
9.423 rounded to the nearest one is 9
Step-by-step explanation:
Answer:
Part a) to find the maximum height of the snowball, you have to differentiate the function. Therefore you get ----> dh/dt= -32x-8 . Now equate this to zero and solve for x. x= (-1)/4 now sub this value in to find h(x) [note: i'm talking about the original function] . I got h max = h((-1)/4) = 9 which is the max height.
Step-by-step explanation:
I'm not too sure about the other questions. Sorry
Answer:
C
Step-by-step explanation:
Here, we want to find which of the expressions have the greatest rate of exponential growth.
The easiest way to go about this is have a substitution for the term t;
Let’s say t = 6
Thus;
h(t) = 1.18^1 = 1.18
K(t) = 0.375^6 = 0.002780914307
f(t) = 1.36^6 = 6.327518887936
g(t) = 0.86^6 = 0.404567235136
Another way to find this is to express each as a sum of 1
f(t) = (1+ 0.36)^t
g(t) = (1-0.14)^t
k(t) = (1-0.625)^t
We can see clearly that out of all the terms in the brackets asides 1, 0.36 is the biggest in value
