Question

What is the value of r of the geometric series?

Answer 1

Answer:

0.8

Step-by-step explanation:

Given the formula for the geometric series expressed as;

$\sum \left \{ {3} \atop {1}} \right 1.3(0.8)^{n-1}$

The nth term of a geometric progression is expressed as;

$T_n = ar^{n-1}$

a is the first term

r is the common ratio

Comparing both equations;

$0.8^{n-1} = r^{n-1}\\Cancel \ the \ powers\\0.8 = r\\r = 0.8$

Hence the value of r of the geometric series is 0.8

Answer 2

Answer:

A

Step-by-step explanation:

Just took test