Solve for m 3m-4=5m+10
2 answers:
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Mean = $ 4. 72
Median = $ 4. 5
Mode = No mode
MAD = $ 4. 8
IQR = $ 0. 5
Measure of center = $ 4. 5
Measure of variability = $ 2. 50
<h3>How to determine the values</h3>Given the data;
$3.50, $4.25, $6, $4.75, $5.80, $4
Mean = sum of data/ number of data values
Mean =
Mean = $ 4. 72
Median is the number in the center when the data is arranged in an ascending order
$3. 50, $4, $4. 25, $4. 75, $5. 80, $6
Median =
Median = $ 4. 5
Mode is the number with the highest repeats.
From the given data, none of the numbers was repeated.
Thus, there is no mode.
MAD, mean absolute deviation = |data value - mean|
MAD =
MAD =
MAD = $ 4. 8
IQR, interquartile range = Quartile 3 - quartile 1
IQR = 4. 75 - 4. 25
IQR = $0. 5
Note that the mean and median are the most common measures of center.
A measure of variability is a single number that is used to describe the spread of a data set
The measure of the center best for the data is the median = $4. 5
Measure of variability = range = highest value - lowest value = $6 - $3. 50 = $2. 50
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