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jok3333 [9.3K]
3 years ago
8

Graph the line with slope -3/4, passing through the points −3−3 .

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
Hello:
equation is the line is : y = ax+b        a is a slope
 y = (-3/4)x+b
<span>passing through the point (−3;−3) :   -3 =(-3/4)(-3)+b
y = (-3/4)x-(21/4)

</span>We draw the <span>Graph by two points : A(-3;-3)  B(0;-21/4)</span>

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No question is asked so I'm not sure what you are looking for but below I calculated the point where the two equations intersect:
y - x = 4 → y = x + 4
y = - x² + 6x
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when x = 4, then y = x + 4 = 4 + 4 = 8 → (4,8)
when x = 1, then y = x + 4 = 1 + 4 = 5 → (1,5)

The line and parabola intersect at two points: (4,8) and (1,5)



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