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Zanzabum
3 years ago
13

Which steps can be done to both sides of the equation to determine the value of x? 3.2 x - 9.6= 38.4

Mathematics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

add both sides ny 9.6 and divide both sides by 3.2, hope this helps!

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xenn [34]

(x) {}^{2}  \\  = (y) {}^{2}  \times 2 - 3 \\  = y

7 0
3 years ago
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Solve the inequality: |2x+5|>0.5
anyanavicka [17]

Answer:

Step-by-step explanation:

Divide all three terms by 2 to isolate x:

|x + 5/2| > 0.25

Case 1:  x + 5/2 > 0.25 (no absolute value symbol needed), or x > -2.25

Case 2:   -(x + 5/2) > 0.25.  Multiplying both sides by -1 yields

                 x + 5/2 < -0.25.  Subtracting 5/2 from both sides:  x < 5.45

The solution set is    -2.25 < x < 5.45.

8 0
3 years ago
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Arc measures and arc lengths , could you show work also
natima [27]

17. Arc AB has a measure of 90 degrees. This means the angle subtending this arc (angle APB) is a right angle, and so triangle PAB is is a right triangle. The sides of the triangle AP and BP have length equal to the radius of the circle. By the Pythagorean theorem,

AP^2+BP^2=AB^2\implies AB=\sqrt{3^2+3^2}=3\sqrt2

so the answer is A.

20. To find the measure of arc AUB, we need to find the measure of the central angle AQB. This angle is part of the quadrilateral AQBP, which is a kite because we're given that PQ and AB are perpendicular.

Arc AVB has measure 60 degrees, so the central angle subtending it (angle APB) also has measure 60 degrees. PQ bisects this angle, so angle APQ has measure 30 degrees.

QA is tangent to circle P, so angle PAQ is a right angle. The sum of the measuers of the interior angles of any triangle is 180 degrees, so

m\angle APQ+m\angle PAQ+m\angle AQP=180^\circ\implies m\angle AQP=60^\circ

PQ also bisects the angle AQB, so that m\angle AQB=2m\angle AQP, and therefore the angle AQB has measure 120 degrees, which in turn is the measure of arc AUB.

4 0
3 years ago
Fencing a horse corral carol has 2400 ft of fencing to fence in a rectangular horse corral. (a) find a function that models the
Vanyuwa [196]

Here it is given that the width is x ft and total length of the fence is 2400 ft .

Let the length be y ft

So we have

2(x+y) =2400&#10;\\&#10;x+y=1200&#10;\\&#10;y = 1200 -x

Let A represents area, and area is the product of length and width .

So we get

A = x y

Substituting the value of y, we will get

A = x (1200-x)= 1200x -x^2

Second part

The area is maximum at the vertex, and vertex is

x = - \frac{1200}{2(-1)} = 600 feet

And

y=1200-x = 1200-600 = 600 feet

And that's the required dimensions .

8 0
3 years ago
If f(1)=3 and f(n)=-2f(n-1)+1,then f(5)=
Drupady [299]
F(5) = - 2f(4) + 1
f(4) = -2f(3) + 1
f(3) = -2f(2) + 1
f(2) = -2f(1) + 1
Therefore:
 f(2) = -2(3) + 1 = -5
f(3) = -2(-5) + 1 = 11
f(4) = -2(11) + 1 = -21
Therefore f(5) = -2(-21) + 1 = 43
5 0
4 years ago
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