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3 years ago

Zack had 20 people show up for his first exercise class he had 36 come to second class what is the percent increased

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

The percent increase is 80%

Step-by-step explanation:

Percent increase is given by:

$Percent\ Increase=\frac{Increase}{Previous\ value}*100\\While\\Increase= New\ value - Old\ value\\$

Here

New value = 36

Old Value = 20

Increase = 36-20 = 16

So,

$Percent\ increase=\frac{16}{20}*100\\=0.8*100\\=80\%$

Hence,

The percent increase is 80%

Keywords: Percentage, Percent

Learn more about percentage at:

#LearnwithBrainly

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10. Write the ratio as a fraction in simplest form. 12 : 42

Pavel [41]

Answer:

2/7

Step-by-step explanation:

12 : 42 is the same as 12/42

simplify the fraction by dividing the numerator and denominator by 6

you get 2/7

8 0

3 years ago

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ANSWER PLEASE !! -2x-5=10 4x+2y=8 -6x+2y=12

son4ous [18]

Answer:

x= -15/2 y=-33/2

Step-by-step explanation:

i dont know how you want to solve it but if it is "system of equations" then first solve for the first variable in on e of the equations, then substitute the result into the other equation.

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2 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Factorise 9w² - 100

ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

In this question, the expression $(9\, w^{2} - 100)$ is the difference between two terms: $9\, w^{2}$ and $100$ .

$9\, w^{2}$ is the square of $3\, w$ . That is: $(3\, w)^{2} = 9\, w^{2}$ .
On the other hand, $10^{2} = 100$ .

Hence:

$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

Apply the fact that $a^{2} - b^{2} = (a - b) \, (a + b)$ to factorize this expression. (In this case, $a = 3\, w$ whereas $b = 10$ .)

$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

8 0

3 years ago

Please include an explanation so I know how to do this. Thanks!

klasskru [66]

Hello there,

So we are trying to find out is the angle ∠BAC in degrees.

So what we are going to do is. . .25- (2x-10)°.

That answer would be -2x+35.

So ∠BAC= -2x+35°.
Hope this helps.

~Jurgen

7 0

3 years ago

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