Answer:
AB // CD and AD // BC, then ABCD is a parallelogram
Step-by-step explanation:
Step 2: Show AD // BC
A = (-3 , 3) and D = (0 , 0)
Find the slope of AD
![m_{AD}=\frac{0-3}{0--3}=\frac{-3}{3}=-1](https://tex.z-dn.net/?f=m_%7BAD%7D%3D%5Cfrac%7B0-3%7D%7B0--3%7D%3D%5Cfrac%7B-3%7D%7B3%7D%3D-1)
B = (2 , 5) and C = (5 , 2)
![m_{BC}=\frac{2-5}{5-2}=\frac{-3}{3}=-1](https://tex.z-dn.net/?f=m_%7BBC%7D%3D%5Cfrac%7B2-5%7D%7B5-2%7D%3D%5Cfrac%7B-3%7D%7B3%7D%3D-1)
The slope of AD = the slope of BC
So AD // BC because they have the same slope
Step 3:
Each two opposite sides are parallel in quadrilateral ABCD
So the quadrilateral is a parallelogram
Answer:
infinite
Step-by-step explanation:
X=5, should be right correct me if i’m wrong.
Answer:
6 units long.
Step-by-step explanation:
Given:
A polygon drawn on a graph.
In order to determine the distance of the horizontal line at the top, we find the coordinates of the end points and then use distance formula to find the exact distance.
Let us label the polygon as ABCD as shown below. AB is the length of the horizontal line.
Coordinates of A are
as seen in the graph.
Coordinates of B are
as seen in the graph.
Now, distance formula for two points
is:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d_{AB}=\sqrt{(3-(-3))^2+(4-4)^2}\\d_{AB}=\sqrt{(3+3)^2+0}\\d_{AB}=\sqrt{36}=6\ units](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%5C%5Cd_%7BAB%7D%3D%5Csqrt%7B%283-%28-3%29%29%5E2%2B%284-4%29%5E2%7D%5C%5Cd_%7BAB%7D%3D%5Csqrt%7B%283%2B3%29%5E2%2B0%7D%5C%5Cd_%7BAB%7D%3D%5Csqrt%7B36%7D%3D6%5C%20units)
Therefore, the horizontal line at the top is 6 units long.