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ValentinkaMS [17]
3 years ago
7

What is the difference, in meters, between the length of the longest line and the length of the shortest line?

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

Range = 3.169m

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the difference between the shortest and the longest

This question implies that we calculate the range.

Range = Longest - Shortest

From the table, we have:

Longest = 8.7m

Shortest = 5.531m

So, we have:

Range = 8.7m- 5.531m

Range = 3.169m

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Option C

Step-by-step explanation:

Option c is right answer

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Bruh your in high school yo know this stuff just make everything a decimal to get your answer. Lol you really forgot this?

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Darius and Barb are playing a video game in which the higher score wins the game. Their scores are shown below. Darius’s scores:
Bumek [7]

Answer:

Darius is correct if only the median score is considered.

Step-by-step explanation:

Darius scores are; 96, 54,120, 87, 123

arrange the scores in increasing order;

54,87,96,120,123

mean = (54+87+96+120+123)/5 =480/5 =96

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Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
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