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yaroslaw [1]
3 years ago
6

Find the equation on the line.

Mathematics
1 answer:
babunello [35]3 years ago
4 0
It’s y=1/3x-2 I hope it’s help u
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Milton purchases of 5 gallon aquarium for his bedroom to fill the ground with water uses the container with the capacity of 1 qu
fgiga [73]
We know that

the capacity of container is 1 quart--------> 0.25 gallon------> 1/4 gallon
so
1/4 gallon-----------------> 1 time
5 gallons----------------> X times?
X=5/(1/4)--------> X=20 times

the answer is
20 times
8 0
3 years ago
−2/3(3 - 1/2)(-1) = ?
chubhunter [2.5K]

The correct answer would be <u><em>B. 2 - 1/3</em></u>

8 0
3 years ago
four friends are planning to meet at the local park. Mary and Teresa jog to the park. Kevin rides his bike to the park, and Manu
taurus [48]
Not sure this is a hard one
4 0
4 years ago
What is the slope of the line shown below? PLEASE HELP
NikAS [45]

Answer:

C. 2

Step-by-step explanation:

The grid markings are the same distance apart in the x- and y-directions, so a line with slope 1 will make a 45° angle with the x-axis. Your line is steeper than that, so has a slope more than 1.

Your line goes up to the right, so its slope is positive.

The only answer choice that is a positive number more than 1 is ...

... C. 2

_____

The slope is computed as the ratio of rise (vertical change) to run (horizontal change). The two marked points tell you the vertical change is from y=-4 to y=6, a change of 6-(-4) = 10. The horizontal change is from x=1 to x=6, a change of 6-1 = 5.

Then the ratio of rise to run is 10/5 = 2. This matches answer C.

6 0
3 years ago
Could I get some help with this question on Trigonometric Identities?
Oksana_A [137]
\bf 1-\cfrac{tan(\theta )cos(\theta )}{csc(\theta )}\implies 1-\cfrac{\frac{sin(\theta )}{cos(\theta )}cos(\theta )}{csc(\theta )}&#10;\\\\\\&#10;\boxed{1-\cfrac{\frac{sin(\theta )}{\underline{cos(\theta )}}\cdot \underline{cos(\theta )}}{\frac{1}{sin(\theta )}}\implies 1-\cfrac{sin(\theta )}{\frac{1}{sin(\theta )}}}\implies 1-sin(\theta )sin(\theta )
8 0
4 years ago
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