Answer:
what did you need to know :(
We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in
.
Let's try
even though we are forbidden to put 4 inside
we are still able to do so.
So
what we just got is the upper limit of the range. The lower limit is
.
So the range is just
.
Hope this helps :)
Answer:
3(x + 9)(x + 2)x = 0
Step-by-step explanation:
xv1 = −9
xv2 = −2
xv3 = 0