Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides? It would be a great he

Question

4 years ago

10

lp

1 answer:

bija089 [108] · Answer 1 · 2021-12-06T20:32:39+03:00

Answer: AC= 10 cm and CE= 5 cm

Step-by-step explanation:

In the given picture, Δ ADE is a right triangle

∴ By Pythagoras theorem,

$AD^2+DE^2=AE^2\\\Rightarrow\ (8+4)^2+9^2=AE^2\\\Rightarrow\ AE^2=12^2+9^2\\\Rightarrow\ AE^2=144+81=225\\\Rightarrow\ AE=15\ cm$

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

$\frac{AB}{AC}=\frac{AD}{AE}\\\Rightarrow\frac{8}{AC}=\frac{12}{15}\\\Rightarrow\ AC=\frac{8\times15}{12}\\\Rightarrow\ AC=10\ cm$

Now, AE=AC+CE

⇒CE=AE-AC

⇒CE=15-10=5 cm