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3 years ago

J^2+5• 10 if j=2,the value of the following expression is 90.

Mathematics

1 answer:

Serhud [2]3 years ago

6 0

Answer:

j^2+50

Step-by-step explanation:

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Express the limit as a definite integral on the given interval.

san4es73 [151]

9514 1404 393

Answer:

$\displaystyle\int^5_2 {(3x^3-7x)} \, dx$

Step-by-step explanation:

The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.

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3 years ago

Estimate the measure of

Lelu [443]

Answer:

148°

Step-by-step explanation:

it is very close to the 150 line and the option closest to 150 is 148

8 0

3 years ago

Read 2 more answers

When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the

Sladkaya [172]

We start with $2 x^{2} -20x-53$ and wish to write it as $a(x+d) ^{2} +e$

First, pull 2 out from the first two terms: $2( x^{2} -10x)-53$

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have $x^{2} -10x$ and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: $x^{2} -10x+25=(x-5) ^{2}$

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have $2( x-5) ^{2}-53$ and when we multiply that out it does not give us what we started with. It gives us $2 x^{2} -20x+50-53=2 x^{2} -20x-3$

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: $2(x-5) ^{2}-53-50$ which gives us the final expression we seek:

$2(x-5) ^{2}-103$

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e = -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106

7 0

3 years ago

If sin(x) = squareroot 2 over 2 what is cos(x) and tan(x)

Bumek [7]

Answer:

cos(x) = square root 2 over 2; tan(x) = 1

Step-by-step explanation:

$\frac{\sqrt{2} }{2}$

was, before it was rationalized,

$\frac{1}{\sqrt{2} }$

Therefore,

$sin(x)=\frac{1}{\sqrt{2} }$

The side opposite the reference angle measures 1, the hypotenuse measures square root 2. That makes the reference angle a 45 degree angle. From there we can determine that the side adjacent to the reference angle also has a measure of 1. Therefore,

$cos(x)=\frac{1}{\sqrt{2} }=\frac{\sqrt{2} }{2}$ and

since tangent is side opposite (1) over side adjacent (1),

tan(x) = 1

7 0

3 years ago

What is the value of the geometric sequence for which a1=10 and r=0.5?

tiny-mole [99]

The formula for an infinite geometric sequence is the following:

$S_{∞}= \frac{a_{1}}{1-r}$

Just substitute the values of $a_{1}$ and r into the formula.

$S_{∞}=\frac{10}{1-0.5}$
$S_{∞}=\frac{10}{0.5}$
$S_{∞}= 20$

Therefore, the answer is 20.

3 0

3 years ago