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egoroff_w [7]
3 years ago
10

Which statement describes the relationship between the length of a rain delay and the number of hours of rainfall?

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:  c. during several storms, there were five hours of delay for every eight hours of rain

Step-by-step explanation: i just had this question

 

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A number decreased by two is at most four or at least nine
JulsSmile [24]
x-2  \leq  4

or

x-2   \geq 9
6 0
3 years ago
Read 2 more answers
A triangle has a height of 15 in. and a area of 120 in. What is the length of it's base?
jek_recluse [69]

Answer:

b=16

Step-by-step explanation:

Formula~ 1/2*b*h

1/2*15*b=120

7.5b=120

b=120/7.5

b=16

(you can substitute the value to check-i've done it below)

1/2*16*15=?

if you work it out, the ans will be 120, therefore the ans is correct!

7 0
3 years ago
Tommy bought one dozen donuts. He gave one-sixth of the donuts to his wife. He then gave one-fifth of the remaining donuts to hi
statuscvo [17]

Answer:

8

Step-by-step explanation:

1/6 of 12 is 2

12 - 2 = 10

1/5 of 10 is also 2

10 - 2 = 8

Tommy took 8 donuts to work.

6 0
2 years ago
For a particular event, 709 tickets were sold for a total of $1,780. If students paid $2 per ticket and non students paid $3 per
Alex73 [517]

Answer:

709

Step-by-step explanation:

7 0
3 years ago
Write a polynomial that represents the area of the shaded region
marusya05 [52]
<h3>Answer: x^2-3x+36</h3>

=========================================

Explanation:

The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution

If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.

The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)

To get the shaded area, we subtract the two rectangle areas found above

shaded area = (larger area) - (smaller area)

shaded area = (x^2+2x+1) - (5x - 35)

shaded area = x^2+2x+1 - 5x + 35

shaded area = x^2-3x+36

6 0
3 years ago
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