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2 years ago

The first number is 3 times 3rd number and second number is 2 times the first and equals 12

Mathematics

1 answer:

solong [7]2 years ago

8 0

Answer:

the first number is 6 the second number is 2 the third number is 2

Step-by-step explanation:

take 12 divided by 2 and u get 6 witch is the first number then u also get the second number witch is 2 then u take 6 divided by 3 and u get the third number witch is 2

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In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five tre

yawa3891 [41]

Answer:

$MSE = 10$

Step-by-step explanation:

Given

$SSTR = 200$

$SST = 800$

Required

Determine MSE

This is calculated as:

$MSE = \frac{1}{ddf} * SSE$

Where:

$SSE = SST - SSTR$

$ddf \to$ denominator df

So, we have:

$SSE = 800 - 200$

$SSE = 600$

To calculate the df, we have:

$r = 13$ --- observations

$n = 5$ treatments

So:

$ddf = Total\ df - Numerator\ df$

$Total = n*r-1 = 5*13 -1 = 64$

$Numerator =n - 1 = 5 - 1 =4$

$ddf =64-4=60$

So, we have:

$MSE = \frac{1}{ddf} * SSE$

$MSE = \frac{1}{60} * 600$

$MSE = 10$

6 0

2 years ago

William has ten colored game pieces in a box: 3 yellow pieces, 5 orange pieces, 1 green piece, and 1 red piece. What is the prob

Nutka1998 [239]

Answer:

Step-by-step explanation:

yellow= .30

orange= .50

green= .10

red- .10

6 0

2 years ago

J. Reexamine the sequence 20, 14, 8, 2, ... from the problem

DENIUS [597]

Answer:

The n th of the given sequence is $t_{n} = 26-6 n$

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference is $d = second term- first term = 14-20=-6$

now the nth term of given sequence is

by using formula $t_{n}=a+(n-1)d$

$t_{n}= 20+(n-1)(-6)$

$t_{n}= 20-6 n+6$

final answer:-

$t_{n} = 26-6 n$

<u>verification</u>:-

$t_{n} = 26-6 n$

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

$t_{n} = 26-6 n$

3 0

3 years ago

What is the sum of the first 37 terms of the arithmetic sequence?

lidiya [134]

Answer:

The sum of the first 37 terms of the arithmetic sequence is 2997.

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

$a_{n} = a_{1} + (n-1)*d$

The sum of the first n terms of an arithmetic sequence is given by:

$S_{n} = \frac{n(a_{1} + a_{n})}{2}$

In this question:

$a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6$

We want the sum of the first 37 terms, so we have to find $a_{37}$

$a_{n} = a_{1} + (n-1)*d$

$a_{37} = a_{1} + (36)*d$

$a_{37} = -27 + 36*6$

$a_{37} = 189$

Then

$S_{37} = \frac{37(-27 + 189)}{2} = 2997$

The sum of the first 37 terms of the arithmetic sequence is 2997.

6 0

2 years ago

Find the value of x.

tino4ka555 [31]

Answer:

107

Step-by-step explanation:

x=180-73

x=107

hope it helps

6 0

2 years ago