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Anit [1.1K]
3 years ago
12

A, B, C, OR D. WILL MARK ANSWER BRAINLIEST.

Mathematics
2 answers:
fgiga [73]3 years ago
6 0

Answer:

C

Step-by-step explanation:

all points on the line of the equation y = 1 will have the number 1 as the y-value in each ordered pair

y = 1 is a horizontal line which intersects the y-axis at (0, 1)

yulyashka [42]3 years ago
6 0
C. Bc it goes through 1
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Inside the triangle. In the center.
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Solve the system of equations using the substitution method.
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3 years ago
Choose the group of one-inch cubes that forms a rectangular prism that has the given dimensions. Then find the surface area of t
jeyben [28]

Answer:

Correct group: fourth image

Surface area = 32 in2

Step-by-step explanation:

The dimensions required is 2 x 3 x 2, so in one dimension we need 2 cubes, in a second dimension we need 3 cubes, and in the third dimension we need 3 cubes.

In the first image, we have a 2 x 3 x 3 prism.

In the second image (to the right of the first one), we have a 2 x 4 x 1 prism.

In the third image (below the first one), we have a 3 x 4 x 1 prism.

In the fourth image, we have a 2 x 3 x 2 prism, so this is the correct option.

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6 0
4 years ago
5x-4y-6z = -3<br> X-3y+z=-1<br> -3x-6y+7z=1
PilotLPTM [1.2K]

Answer:

x=-\frac{41}{55},y=\frac{2}{55},z=-\frac{8}{55}

Step-by-step explanation:

5x-4y-6z=-3...............eq(1)\\\\x-3y+z=-1.....................eq(2)\\\\-3x-6y+7z=1.................eq(3)

eq(1)-5\times eq(2)

5x-4y-6z-5(x-3y+z)=-3-5\times (-1)\\\\11y-11z=2\\\\y-z=\frac{2}{11}...................eq(4)

3\times eq(2)+eq(3)

3(x-3y+z)-3x-6y+7z=3\times (-1)+1\\\\-15y+10z=-2\\\\-y+\frac{2}{3}z=-\frac{2}{15}.........eq(5)

eq(4)+eq(5)

y-z-y+\frac{2}{3}z=\frac{2}{11}-\frac{2}{15}\\\\-\frac{1}{3}z=\frac{8}{165}\\\\z=-\frac{8\times 3}{165}\\\\z=-\frac{8}{55}

From eq(4)

y=z+\frac{2}{11}=-\frac{8}{55}+\frac{2}{11}\\\\y=\frac{2}{55}

Substitute the value of y and z in eq(2)

x-3\times \frac{2}{55}-\frac{8}{55}=-1\\\\x-\frac{14}{55}=-1\\\\x=-1+\frac{14}{55}\\\\x=\frac{41}{55}

6 0
4 years ago
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