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MAXImum [283]
3 years ago
12

If -4/3y=-3/4, then y =?

Mathematics
2 answers:
garri49 [273]3 years ago
5 0

Step-by-step explanation:

y=-3/4 ÷ -4/3

y=+9/16‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌

wariber [46]3 years ago
4 0

Answer:

So we have this equation:

\frac{-4}{3y}=\frac{-3}{4}

We can multiply both sides by 4 and 3y:

\frac{-4*4*3y}{3y}=\frac{-3*4*3y}{4}

-4*4=-3*3y

-16 = -9y

Now we divide both sides by 9:

\frac{-16}{-9}=y

And we can remove the minus signs:

\frac{16}{9}=y

If you mean \frac{-4}{3}y=\frac{-3}{4}:

-4y*4=-3*3

-16y = -9

y=\frac{9}{16}

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Sketch the quadratic function f(x) = -2x2 + 4x + 6. Which key feature of the graph is not true?
sertanlavr [38]

Answer:

D is false

Step-by-step explanation:

f(x) = -2x2 + 4x + 6 should be written with a " ^ " to indicate exponentiation:

f(x) = -2x^2 + 4x + 6.

Because of the - sign, we know that the graph of this function opens down, so there is a maximum at the vertex.  We can determine the x-value at the vertex by using the formula x = -b/(2a), which here is x = -4/(2*-2), or 1.

Evaluating f(x) = -2x^2 + 4x + 6 at x = 1, we get -2 + 4 + 6, or 8.  So statement A is true:  there's a max at (1, 8).  This is also the vertex of the graph.

Let's now look at C and D.  We evaluate f(x) at x = 3 and x - 2.  If the output (y) value is 0, we know we have an x - intercept:

f(3) = -2(9) + 4(3) + 6 = 0.  Yes, C is true, (3, 0) is an x-intercept.

f(-2) = -2(4) - 8 + 6 is not 0.  Therefore D is false; (-2, 0) is not an x-intercept.

Look at B:  Let x = 0 and find y:  it's 6.  Thus, (0, 6) is the y-intercept.  B is true.

4 0
3 years ago
Tell whether the equation has one,zero or many solutions -(2x+2)-1=-x-(x+3)
PtichkaEL [24]

- (2x + 2) - 1 = -x - (x + 3)

-2x - 2 - 1 = -x - x - 3

-2x - 3 = -2x - 3

This is an identity and x can be any value

Answer many solutions

3 0
2 years ago
How do i solve this (give steps please)
anygoal [31]

Answer:

42x - 21 - 9x^2

Step-by-step explanation:

basically do the area of the whole rectangle then di the area of one of the empty spaces. then subtract the value of the empty space three times because there are three empty spaces.

4 0
2 years ago
Read 2 more answers
Find all the values of k so that the given points are 29 square units apart. (-5, 5) and (k,0).
Varvara68 [4.7K]
Distance formula between 2 points (x1,y1) and (x2,y2)

D=\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}

D=29 and one point is (-5,5) and the other is (k,0)
sub

29=\sqrt{(-5-k)^{2}+(5-0)^{2}}
29=\sqrt{(-5-k)^{2}+(5)^{2}}
square both sides
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+/-4√51=-5-k
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5+/-4√51=-k
times -1 both sides
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the possible values for k are
k=-5+4√51 or k=-5-4√51

7 0
3 years ago
The table shows some values of a polynomial function, over which interval is the average rate of change of the function positive
nordsb [41]

Answer:

option  1 i think

Step-by-step explanation:

3 0
3 years ago
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