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34kurt
2 years ago
9

Two numbers are the multiplicative inverse of each other if their product is​

Mathematics
1 answer:
AveGali [126]2 years ago
4 0

Answer:

the product is 1

Step-by-step explanation:

if you have any number, its multiplicative inverse is 1/ that number

for example 23 has multiplicative inverse 1/23 if you calculate the product you will simplify and always get 1 as a result.

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Give all the basic trigonometric functions that satisfy the condition <img src="https://tex.z-dn.net/?f=f%28x%29%20%5Cneq%200" i
prohojiy [21]

Answer:

i need points lol

Step-by-step explanation:

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5 0
2 years ago
Can you please answer the question?
Roman55 [17]

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}

\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}

\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}

\tan \alpha + 1 + \cot \alpha

\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

\frac{1}{\cos \alpha \cdot \sin \alpha} + 1

\sec \alpha \cdot \csc \alpha + 1

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
A triangle has side lengths of 11 cm and 9 cm. which could be the value of the third side, 20 cm or 15 cm?
EleoNora [17]
The third side measures exactly 15 centimetres (cm).
6 0
3 years ago
84/120 simplified as a fraction
Pachacha [2.7K]
7/10 because when you simplify 84/120 the lowest terms is 7/10.
6 0
2 years ago
Hello I made a pad let GC for people that stays up all night, and on this gc you can make friends or meet new people. Here's the
inessss [21]

Answer:

no

Step-by-step explanation:

For all the kids out there don't trust these I.D.1.0.T.S they are just trying to get your info to either do stuff 2 you or just laugh at you please don't fall for these du'mb tricks. Stay safe

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