Question

A combined total of 39000 is invested in two bonds that pay 5% and 6.5% simple interest. The annual interest is 235500 how much is invested in each bond?

Answer 1

Answer:

$12000 at 5%

$27000 at 6.5%.

Step-by-step explanation:

Let x represent amount invested at 5% and y represent amount invested at 6.5%.

We have been given that a combined total of 39000 is invested in two bonds. We can represent this information in an equation as:

$x+y=39000...(1)$

We are also told that the annual interest rate is 2355.00. We can represent this information in an equation as:

$0.05x+0.065y=2355...(2)$

Upon substituting equation (1) in equation (2), we will get:

$0.05x+0.065(39000-x)=2355$

$0.05x+2535-0.065x=2355$

$-0.015x+2535=2355$

$-0.015x=2355-2535$

$-0.015x=-180$

$\frac{-0.015x}{-0.015}=\frac{-180}{-0.015}$

$x=12000$

Therefore, an amount of $12,000 is invested at 5%.

Upon substituting $x=12000$ in equation (1), we will get:

$12000+y=39000$

$y=39000-12000$

$y=27000$

Therefore, an amount of $27,000 is invested at 6.5%.